C program to print given numbers as a pyramid

Posted on September 12, 2012June 19, 2017 by Sandeepa Nadahalli

Write a C program to print given numbers as a pyramid.
In this program we use the simple for statements to produce the patterns.
This program prints the following output,
1
232
34543
4567654
567898765
Read more about C Programming Language . and read the C Programming Language (2nd Edition). by K and R.

–>

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* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact [email protected]
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* and browse!
* 
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***********************************************************/

#include<stdio.h>


void display(int start, char *str){
    
    int i,j;
    
    
    for(i=start; i<=(start+start); i++)
    
    printf("%c",str[i]);
    
    for(j=i-2;j>=start;j--)
    
    printf("%c",str[j]);
    
}


main(){
    
    char str[]="123456789";
    
    int i, j;
    
    for(i=0;i<5;i++){
        
        display(i, str);
        
        printf("n");
        
    }
    
}

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C program to convert a Binary number into its equivalent Decimal, Octal and Hexadecimal numbers.

Posted on October 19, 2011August 11, 2017 by Sandeepa Nadahalli

C Program to convert binary number into its equivalent Decimal, Octal, and Hexadecimal representations. In this program we convert a binary number to decimal. Then convert that decimal number to octal and Hexadecimal equivalent.

The program implements various functions to do the job.

binary_to_decimal : Convert given binary number to it’s decimal equivalent
decimal_to_octal : Convert from decimal to octal
decimal_to_hex : Convert from decimal to hexadecimal

The main function takes care of getting input from user, calling the above functions and displaying the results.

The Program

	#include <stdio.h>

	/*
	* Function to convert a given decimal number to its
	* hexadecimal equivalent.
	*/
	int decimal_to_hex(long number, char *hexstr, int pos) {
	long i;
	int new_position, n;
	char hexchar;

	new_position = pos;

	if(number > 0) {
	i = number % 16;
	n = number / 16;
	new_position = decimal_to_hex(n, hexstr, pos);
	if(i >= 10) {
	switch(i) {
	case 10: hexchar = 'A'; break;
	case 11: hexchar = 'B'; break;
	case 12: hexchar = 'C'; break;
	case 13: hexchar = 'D'; break;
	case 14: hexchar = 'E'; break;
	case 15: hexchar = 'F'; break;
	}
	} else {
	hexchar = '0' + i;
	}
	hexstr[new_position++] = hexchar;
	hexstr[new_position] = '\0';
	}
	return new_position;
	}

	/*
	* Function to convert a given binary number to
	* its decimal equivalent.
	*/
	int binary_to_decimal(int num) {
	int rem, base = 1, decimal_number = 0;
	while( num > 0) {
	rem = num % 10;
	if((rem == 0) \|\| (rem == 1)) {
	decimal_number = decimal_number + rem * base;
	num = num / 10 ;
	base = base * 2;
	} else {
	return -1; // Invalid binary number
	}
	}
	return decimal_number;
	}

	/*
	* Function to convert a given decimal number in to
	* its octal equivalent.
	*/
	int decimal_to_octal(int number) {
	int octal_number = 0, rem, base = 1;

	while(number > 0) {
	rem = number % 8;
	octal_number = octal_number + rem * base;
	base = base * 10;
	number = number / 8;
	}
	return octal_number;
	}

	void main() {
	int binary_numer, decimal_number, octal_number;
	char hexstr[25] = "0";

	printf("Enter a binary number: ");
	scanf("%d", &binary_numer);

	printf("Given Binary number is: %d\n", binary_numer);

	decimal_number = binary_to_decimal(binary_numer);
	if(decimal_number == -1) {
	printf("\nInvalid binary number. Try again.");
	return;
	}
	printf("Its Decimal equivalent is: %d", decimal_number);

	octal_number = decimal_to_octal(decimal_number);
	printf("\nIts octal equivalent is: %d", octal_number);

	decimal_to_hex(decimal_number, hexstr, 0);
	printf("\nIts Hexa Decimal equivalent is: %s", hexstr);
	}

view raw binary_to_octal_decimal_hexadecimal.c hosted with ❤ by GitHub

Sample Output

Binary to decimal, binary to octal, binary to hexadecimal

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Edit1 : 11th August 2017

Added screenshot of sample runs
Moved the code to it’s own Gist
Modified the program to make it more modular

C Program to check the given number is Armstrong or not?

Posted on October 14, 2011 by Sandeepa Nadahalli

C Program to check the given number is Armstrong number or not?. Armstrong number is a number that is the sum of its own digits each raised to the power of the number of digits. Example: 153 = 1^3 + 5^3 + 3^3. Read more about C Programming Language .

/***********************************************************
* You can use all the programs on  www.c-program-example.com
* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact [email protected]
* To find more C programs, do visit www.c-program-example.com
* and browse!
* 
*                      Happy Coding
***********************************************************/


#include<stdio.h>
void main()
{
 int num,num1,arms=0,rem;

 printf("Enter the number:n");
 scanf("%d",&num);
 num1=num;
 while(num>0)
 {
  rem=num%10;
  arms=arms+rem*rem*rem;
  num=num/10;
 }
 if(num1==arms)
 {
  printf(" n%d is an Armstrong number",num1);
 }
 else
 {
  printf("n%d is NOT an Armstrong number",num1);
 }

}

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C Program to check the given number is perfect or not.

Posted on October 14, 2011 by Sandeepa Nadahalli

C Program to check the given number is perfect or not?. Perfect number is a positive integer that is equal to the sum of its proper positive divisors. example 6, divisor of 6 are 1, 2,3. Sum of divisors is 1+2+3=6.
Read more about C Programming Language .

/***********************************************************
* You can use all the programs on  www.c-program-example.com
* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact [email protected]
* To find more C programs, do visit www.c-program-example.com
* and browse!
* 
*                      Happy Coding
***********************************************************/


#include<stdio.h>
int main(){
 int num,i=1,sum=0;

 printf("Enter a number: ");
 scanf("%d",&num);

 while(i<num){
  if(num%i==0)
   sum=sum+i;
  i++;
 }
 if(sum==num)
  printf("%d is a perfect number",i);
 else
  printf("%d is not a perfect number",i);

 return 0;
}

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