K & R C Programs Exercise 4-1.

K and R C, Solution to Exercise 4-1:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
Write a C program which returns the position of the occurrence of sub string t in string s, or -1 if there is none.

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#include<stdio.h>
#include<conio.h>
void main()
{
int flag=0;
char str[80],search[10];
puts("Enter a string:");
gets(str);

puts("Enter search substring:");
gets(search);
flag=strindex(str, search);
if (flag == -1)
{
printf("SEARCH UNSUCCESSFUL! AND POSITION IS:%d",flag);
}
else{
printf("SEARCH SUCCESSFUL! AND POSITION IS:%d",flag);
}
getch();
}

//strindex: returns the right most index of t in s, -1 if none*/
int strindex(char s[], char t[])
{
int k,i,j,pos;
pos = -1;
for(i=0;s[i] != ''; i++)
{
for(j=i, k = 0; t[k] != '' && s[j] == t[k]; j++, k++)
;
if (k > 0 && t[k] == '')
pos=i;
}
return pos;
}
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K & R C Programs Exercise 2-5.

K and R C, Solution to Exercise 2-5:
 K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language, second addition, by Brian W.Keringhan and Dennis M.Ritchie(Prentice Hall,1988). You can learn and solve K&R C Programs Exercise.
Write the C function any(s1, s2), which returns the first location in the string s1 where any character from the string s2 occurs, or -1 if s1 contains no characters from s2.The standard library function strpbrk does the same job but returns a pointer to the location.Read more about C Programming Language .

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***********************************************************/

int any(char s1[], chars2[])
{
int i, j;
for(i=0;s1[i]!='';i++)

for(j=0;s2[[j]!='' ;j++)

if(s1[i]==s2[j])
return i;

return -1;
}
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K & R C Programs Exercise 2-4.

K and R C, Solution to Exercise 2-4:
 K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language, second addition, by Brian W.Keringhan and Dennis M.Ritchie(Prentice Hall,1988). You can learn and solve K&R C Programs Exercise.
Write an alternate version of squeeze(s1,s2) that deletes each character in s1 that matches any character in the string s2.
Compare ,First string with the second string, if any character matched,  delete the matched character of the first string. Read more about C Programming Language .

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*
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***********************************************************/


/*squeeze: delete each char in s1 which is in s2*/
void squeeze(char s1[], chars2[])
{
int i, j, k;
for(i=k=0;s1[i]!='';i++)
{
for(j=0;s2[[j]!='' && s2[j]!=s1[i];j++)
;
if(s2[j]=='')
s1[k++]=s1[i];
}
s1[k]='';
}
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C Program to compare two strings

C Strings:
C Program to accepts two strings and compare them, Finally it prints whether both are equal, or first string is greater than the second or the first string is less than the second string. The string comparison starts with the first character in each string and continues with subsequent characters until the corresponding characters differ or until the end of the strings is reached. Read more about C Programming Language .

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* for personal and learning purposes. For permissions to use the
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* and browse!
* 
*                                  Happy Coding
***********************************************************/              
#include<stdio.h>
#include<conio.h>

void main()
{
 int count1=0,count2=0,flag=0,i;
 char str1[10],str2[10];

 clrscr();
 puts("Enter a string:");
 gets(str1);

 puts("Enter another string:");
 gets(str2);
 /*Count the number of characters in str1*/
 while (str1[count1]!='')
  count1++;
 /*Count the number of characters in str2*/
 while (str2[count2]!='')
  count2++;
 i=0;

 /*The string comparison starts with the first character in each string and
 continues with subsequent characters until the corresponding characters
 differ or until the end of the strings is reached.*/

 while ( (i < count1) && (i < count2))
 {
  if (str1[i] == str2[i])
  {
   i++;
   continue;
  }
  if (str1[i]<str2[i])
  {
   flag = -1;
   break;
  }
  if (str1[i] > str2[i])
  {
   flag = 1;
   break;
  }
 }

 if (flag==0)
  printf("Both strings are equaln");
 if (flag==1)
  printf("String1 is greater than string2n", str1, str2);
 if (flag == -1)
  printf("String1 is less than string2n", str1, str2);
 getch();
}
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Searching in C

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