C Program to copy and concatenate strings without using standard functions.

C Program to copy and concatenate strings without using standard functions.
In this program , we copy one string from another, and without using the standard library function strcpy from string.h .
Here we appends the one string to another without using the strcat function. Read more about C Programming Language .

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***********************************************************/



#include <stdio.h>

void newStrCpy(char *,char *);
void newStrCat(char *,char *);

void main()
{
char str1[80],str2[80];
int opn;
do
{
printf("Press 1- NewStrCpy t 2- NewStrCatt 3- Exitt Your Option?");
scanf("%d",&opn);
switch(opn)
{
case 1: flushall();
printf("n Read the Source String n");
gets(str1);
newStrCpy(str2,str1);
printf(" Copied String: %sn",str2);
break;
case 2: flushall();
printf(" Read the First String n");
gets(str1);
printf(" Read the Second String n");
gets(str2);
newStrCat(str1,str2);
printf("Concatenated String: n");
puts(str1);
break;
case 3: printf(" Exit!! Press a key . . .");
getch();
break;
default: printf(" Invalid Option!!! Try again !!!n");
break;
}
}while(opn != 3);
} /* End of main() */

void newStrCpy(char *d,char *s)
{
while( (*d++ = *s++));
}
void newStrCat(char *s, char *t)
{
while(*s)
s++;
while(*s++ = *t++);
}

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C program To show examples of the strtol function.

C program To show examples of the strtol function.
strtol() function converts the string to the long integer, and strtol() can accept the number in various bases, and converts it into the decimal number or base. Read more about C Programming Language .

/***********************************************************
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*
* Happy Coding
***********************************************************/

#include <stdlib.h>

main()
{
char num[10];

/* Test a valid number */
strcpy(num,"13");

printf("%s(Oct) is %i(Dec)n", num, strtol(num, NULL, 8));
printf("%s(Dec) is %i(Dec)n", num, strtol(num, NULL, 10));
printf("%s(hex) is %i(Dec)n", num, strtol(num, NULL, 16));

puts("----------------------------------");

/* Test a slightly valid number
* Returns the same results as
* above. */
strcpy(num, "13hzcd");

printf("%s(Oct) is %i(Dec)n", num, strtol(num, NULL, 8));
printf("%s(Dec) is %i(Dec)n", num, strtol(num, NULL, 10));
printf("%s(hex) is %i(Dec)n", num, strtol(num, NULL, 16));

puts("----------------------------------");

/* Test an invalid number
* Returns ZERO */
strcpy(num, "hzcd");

printf("%s(Oct) is %i(Dec)n", num, strtol(num, NULL, 8));
printf("%s(Dec) is %i(Dec)n", num, strtol(num, NULL, 10));
printf("%s(hex) is %i(Dec)n", num, strtol(num, NULL, 16));


puts("----------------------------------");

/* Test 0 base.
* This will look at the number
* and decide the base for its self!
*/
strcpy(num, "13");
printf("%s is %i(Dec)n", num, strtol(num, NULL, 0));

strcpy(num, "013");
printf("%s is %i(Dec)n", num, strtol(num, NULL, 0));

strcpy(num, "0x13");
printf("%s is %i(Dec)n", num, strtol(num, NULL, 0));

}
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C Program to demonstrate the strtok function.

C Program to demonstrate the strtok function.
strtok function breaks pointed by the string1 into sequence of tokens, which are sequences of contiguous characters separated by any of the characters that are part of delimiters.
In this program we split the test_string, i,e “string to split up ” to
string
to
split
up
Read more about C Programming Language .

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*
* Happy Coding
***********************************************************/

#include <stdio.h>
#include <string.h>

main()
{

char test_string[50]="string to split up";



char *sub_string;

/* Extract first string */
printf("%sn", strtok(test_string, " "));

/* Extract remaining
* strings */
while ( (sub_string=strtok(NULL, " ")) != NULL)
{
printf("%sn", sub_string);
}
}
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C Program to demonstrate the strstr function.

C Program to demonstrate the strstr function.
strstr function finds the substring in a string. strstr() returns pointer of the first occurrence of the string other wise it returns the null pointer is returned.
In this program strstr returns a pointer into ‘string’ if ‘test’ is found, if not found, NULL is returned. Read more about C Programming Language .

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*
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***********************************************************/


#include <stdio.h>
#include <string.h>

main()
{
char string[]="string to search";
char test[]="sear";
if (strstr(string, test)) puts("String found");

}
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C Program to demonstrate strpbrk function.

Write C programt to demonstrate strpbrk function.
strpbrk function locate the first occurrence pointed by the of string s1 from the string pointed to by s2. In this program, We Turns miscellaneous field separators into just a space separating tokens for easy parsing by SSCANF. Eventually, the character separators and replacement character will be passed in as strings. Read more about C Programming Language .

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*
* Happy Coding
***********************************************************/
#include <stdio.h>
#include <string.h>
#include <strings.h>

#define LINE_BUF 100

void find_comment(char *);

main()
{
char line[LINE_BUF];
char *sep;
int var1, var2;

while (fgets(line, LINE_BUF, stdin)) {

/*
* Check this out: Since SEP is a pointer to type char, when line is
* assigned to sep, really the first address is assigned to sep. LINE
* is the address of the start of the string. In contrast, LINE[0]
* is the first character of the string.
*/

sep = line;

while (sep != 0) {
sep = strpbrk(line, ";.&:,");
if (sep != 0)
*sep = ' ';
}
fputs(line, stdout);
}
return 0;
}
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K & R C Programs Exercise 5-5.

K and R C, Solution to Exercise 5-5:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
C Program to write the versions of the library functions strncpy, strncat, and strncmp, which operate on at most the first n characters of their argument strings.
For example, strncpy(s, t, n) copies at most n characters of t to s. Read more about C Programming Language .

/***********************************************************
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* and browse!
*
* Happy Coding
***********************************************************/

/*strncpy: copy n characters from t to s*/
void strncpy(char *s, char *t, int n)
{
while(*t && n--> 0)
*s++ = *t++;
while( n--> 0)
*s++ = '';
}

/*strncat: concatenate n characters of t to end of s*/
void strncat(char *s, char *t, int n)
{
void strncpy(char *s, char *t, int n);
int strlen(char *);
strncpy(s+strlen(s), t, n);
}

/*strncmp: comapre at most n characters of t with s */
int strncmp(char *s, char *t, int n)
{
for( ; *s == *t; s++, t++)
if(*s == '' || --n <= 0)
{
return 0;
}
return *s - *t;
}
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K & R C Programs Exercise 5-4.

K and R C, Solution to Exercise 5-4:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
C Program, that returns 1 if the string t occurs at the end of the string s, and zero otherwise. Read more about C Programming Language .

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* contact info@c-program-example.com
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* and browse!
*
* Happy Coding
***********************************************************/


#include <stdio.h>

//finds the string length, standard "strlen" function
int str_len(char *s)
{
int n;

for(n = 0; *s != ''; s++)
{
n++;
}
return n;
}

int str_cmp(char *s, char *t)
{
for(;*s == *t; s++, t++)
if(*s == '')
return 0;
return *s - *t;
}


int str_end(char *s, char *t)
{
int Result = 0;
int s_length = 0;
int t_length = 0;

/* get the lengths of the strings */
s_length = str_len(s);
t_length = str_len(t);

/* check if the lengths mean that the string t could fit at the string s */
if(t_length <= s_length)
{
/* advance the s pointer to where the string t would have to start in string s */
s += s_length - t_length;

/* and make the compare using strcmp */
if(0 == str_cmp(s, t))
{
Result = 1;
}
}

return Result;
}
int main(void)
{
char Str1[8192] ;
char Str2[8192] ;
char Str3[8192] ;
printf("n Enter the first string: n");
scanf("%s",Str1);
printf("n Enter the second string: n");
scanf("%s",Str2);
printf("n Enter the third string: n");
scanf("%s",Str3);
printf("String one is (%s)n", Str1);
printf("String two is (%s)n", Str2);
printf("String two is (%s)n", Str3);

if(str_end(Str1, Str2))
{
printf("The string (%s) has (%s) at the end.n", Str1, Str2);
}
else
{
printf("The string (%s) doesn't have (%s) at the end.n", Str1, Str2);
}
if(str_end(Str1, Str3))
{
printf("The string (%s) has (%s) at the end.n", Str1, Str3);
}
else
{
printf("The string (%s) doesn't have (%s) at the end.n", Str1, Str3);
}



return 0;
}


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K & R C Programs Exercise 4-13.

K and R C, Solution to Exercise 4-13:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
Write a C Program to reverse the string using the recursive methods.
In this program reverse determines the length of the string and then calls the reverser, which reverses the string s in place. Read more about C Programming Language .

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*
* Happy Coding
***********************************************************/
#include<stdio.h>
/* reverse: reverse the string s in place */
void reverse(char s[])
{

void reverser(char s[], int i, int len);
reverser(s,0,strlen(s));
}

/* reverser: reverse string s in place recursive */
void reverser(char s[], int i, int len)
{
int c, j;
j = len - (i + 1);
if(i < j)
{
c = s[i];
s[i] = s[j];
s[j] = c;
reverser(s, ++i, len);
}
}

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K & R C Programs Exercise 4-7.

K and R C, Solution to Exercise 4-7:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
Write C program that will push back an entire string onto the the input.
ungets calls the routine ungetch len times, each time pushing back a character from the string s onto the input. ungets pushes the string back in reverse order.
The routine ungets does not need to worried about the buf and bufp. The routine ungetch handles buf, bufp, and error handling. Read more about C Programming Language .

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* programs for commercial purposes,
* contact info@c-program-example.com
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* and browse!
*
* Happy Coding
***********************************************************/

#include<stdio.h>
/*ungets: push string back onto the input*/

void ungets(char s[])
{
int len=strlen(s);
void ungetch(int);
while (len >0)
ungetch(s[--len]);
}
int main(void)
{
char *s = "oh! this is for testing!";
int c;

ungets(s);
while ((c = getch()) != EOF)
putchar(c);
return 0;
}
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K & R C Programs Exercise 4-1.

K and R C, Solution to Exercise 4-1:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
Write a C program which returns the position of the occurrence of sub string t in string s, or -1 if there is none.

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*
* Happy Coding
***********************************************************/

#include<stdio.h>
#include<conio.h>
void main()
{
int flag=0;
char str[80],search[10];
puts("Enter a string:");
gets(str);

puts("Enter search substring:");
gets(search);
flag=strindex(str, search);
if (flag == -1)
{
printf("SEARCH UNSUCCESSFUL! AND POSITION IS:%d",flag);
}
else{
printf("SEARCH SUCCESSFUL! AND POSITION IS:%d",flag);
}
getch();
}

//strindex: returns the right most index of t in s, -1 if none*/
int strindex(char s[], char t[])
{
int k,i,j,pos;
pos = -1;
for(i=0;s[i] != ''; i++)
{
for(j=i, k = 0; t[k] != '' && s[j] == t[k]; j++, k++)
;
if (k > 0 && t[k] == '')
pos=i;
}
return pos;
}
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