K & R C Programs Exercise 4-8.

K and R C, Solution to Exercise 4-8:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
C Program to modify the K & R C Programs Exercise 4-7, Suppose there will never be more than one character of pushback. Modify getch and ungetch accordingly. Read more about C Programming Language .

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#include <stdio.h>
char buf = 0;

//getch: get a (possible pushed character back) character
int getch(void)
{
 int c;
 if(buf != 0)
  c = buf;
 else
  c getchar();
 buf = =0;
 return c;
}

/*ungetch: push string back onto the input*/
void ungetch(int c)
{
 if (buf != 0)
  printf("ungetch: too many characters!n");
 else
  buf = c;
}
int main(void)
{
 int c;

 while ((c = getch()) != EOF) {
  if (c == '/') {
   putchar(c);
   if ((c = getch()) == '*') { 
    ungetch('!');
   }         
  } 
  putchar(c);               
 }
 return 0;
}
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K&R C Program Exercise 1-06

K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language, second addition, by Brian W.Keringhan and Dennis M.Ritchie(Prentice Hall,1988). You can learn and solve K&R C Programs Exercise. C Program to Verify that the expression getchar() != EOF is 0 or 1. The program reads the charecters from the standard input and return 1, while getchar has a charecter to read it. When the program encounters the end of file,then it prints 0.Read more about C Programming Language .

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***********************************************************/




#include <stdio.h>

int main(void)
{
printf("Press a key. ENTER would be nice :-)nn");
printf("The expression getchar() != EOF evaluates to %dn", getchar() != EOF);
return 0;
}
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C Program to demonstrate the ‘getchar’ function.

Program to demonstrate the getchar function. The program will read data entered via the keyboard. And returns the number of characters entered. Read more about C Programming Language .

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* and browse!
*
* Happy Coding
***********************************************************/

#include <stdio.h>

#define RETURN 'n' /* n == return in UNIX
r == return in DOS */

main()
{
int count=0;
puts("Please enter some text.");
/* Count the letters in the 'stdin'
buffer. */
while ( getchar() != RETURN) count++;

printf("You entered %d charactersn", count);
}
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C program to find the character type.

C Program to find the Character types. Here we used the isdidit(), isalpa(), and isspace() functions.isdigit() function returns true if argument is a decimal digit, otherwise false. isalpa() function returns true if argument is a defined set of characters in c, otherwise false. isspace() function returns true if argument is a white space character (one of ‘ ‘ ‘f’ ‘n’ ‘r’ ‘t’ ‘v’), otherwise false. Read more about C Programming Language .

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* You can use all the programs on www.c-program-example.com
* for personal and learning purposes. For permissions to use the
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* contact info@c-program-example.com
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* and browse!
*
* Happy Coding
***********************************************************/



#include <stdio.h>
#include <ctype.h>

#define FALSE 0
#define TRUE 1

/* function declarations */
int char_type(char);

main()
{
char ch;
/* get a character from the keyboard */
printf(" Please enter a charcater => ");
ch = getc(stdin);

char_type(ch); /* Figure out the character type */
}


int char_type(char ch)
{
/* returns non zero if A-Z or a-z */
if ( isalpha(ch) != FALSE)
printf("%c is an Alpha character.n",ch);

/* returns non zero if 0-9 */
if ( isdigit(ch) != FALSE)
printf("%c is a numeric character.n",ch);

/* returns non zero if a space, CR, Tab, NL FF */
if ( isspace(ch) != FALSE)
printf("%c is white spacen", ch);

}
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