K & R C Programs Exercise 7-8.

K and R C, Solution to Exercise 7-8:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
C Program to print a set of files, starting each new one on a new page, with a title and running page for each file Read more about C Programming Language .
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* programs for commercial purposes,
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*
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***********************************************************/

#include<stdio.h>
#include<stdlib.h>

#define MAXBOT 3
#define MAXHDR 5
#define MAXLINE 100
#define MAXPAGE 66

/*print: print files - each new one on a new page */
main(int argc, char *argv[])
{

FILE *fp;
void fileprint(FILE *fp, char *fname);

if(argc == 1)
fileprint(stdin," ");
else
if((fp = fopen(*++argv,"r")) == NULL) {
fprintf(stderr,"find:can't open %sn",*argv);
exit(1);
} else {

fileprint(fp, *argv);
fclose(fp);
}
return 0;
}


//fileprint: print file name
void fileprint(FILE *fp, char *fname)
{
int lineno, pageno = 1;
char line[MAXLINE];
int heading(char *fname, int pageno);
lineno = heading(fname, pageno++);
while(fgets(line, MAXLINE, fp) != NULL) {
if(lineno == 1) {
fprintf(stdout,"f");
lineno = heading(fname, pageno++);
}
fputs(line, stdout);
if(++lineno > MAXPAGE - MAXBOT)
lineno = 1;
}
fprintf(stdout,"f");
}

//heading: put heading and enough blank lines
int heading(char *fname, int pageno)
{
int ln = 3;
fprintf(stdout,"nn");
fprintf(stdout,"%s page %dn", fname, pageno);
while(ln++ < MAXHDR)
fprintf(stdout,"n");
return ln;
}
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K & R C Programs Exercise 7-6.

K and R C, Solution to Exercise 7-6:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
Write a C Program to compare two files, printing the first line where they differ.
Read more about C Programming Language .
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* programs for commercial purposes,
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* and browse!
*
* Happy Coding
***********************************************************/

#include<stdio.h>
#include<stdlib.h>
#include<string.h>

#define MAXLINE 100
/*comp: compare two file, printing the first line where they differ*/
main(int argc, char *argv[])
{
FILE *fp1, *fp2;
void filecomp(FILE *fp1, FILE *fp2);
if(argc != 3){
fprintf(stderr,"comp:need two file namesn");
exit(1);
} else {
if((fp1 = fopen(*++argv, "r")) == NULL) {
fprintf(stderr, "comp:can't open %sn",*argv);
exit(1);
} else if((fp2 = fopen(*++argv, "r")) == NULL) {
fprintf(stderr, "comp:can't open %sn",*argv);
exit(1);
}else {
filecomp(fp1,fp2);
fclose(fp1);
fclose(fp2);
exit(0);

}
}
}

//filecomp: compare two files -a line at a time
void filecomp (FILE *fp1, FILE *fp2)
{
char line1[MAXLINE], line2[MAXLINE];
char *lp1 = *lp2;
do{
lp1 = fgets(line1, MAXLINE, fp1);
lp2 = fgets(line2, MAXLINE, fp2);
if(lp1 == line1 && lp2 == line2){

if(strcmp(line1,line2) !=0) {
printf("First difference in linen%sn",line1);
lp1 = lp2 = NULL;
}
} else if(lp1 != line1 && lp2 == line2)
printf("end of first file at linen%sn",line2);
else if(lp1 == line1 && lp2 == line2)
printf("end of second file at line n%sn",line1);

}while(lp1 == line1 && lp2 == line2);
}



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K & R C Programs Exercise 7-5.

K and R C, Solution to Exercise 7-5:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
Rewrite the postfix calculator of chapter 4 to use scanf and/or sscanf to do the input number conversion.
Read more about C Programming Language .
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* You can use all the programs on www.c-program-example.com
* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact info@c-program-example.com
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* and browse!
*
* Happy Coding
***********************************************************/



#include<stdio.h>
#include<math.h> /*for atof()*/
#define MAXTOP 100 /* max size of operand or operator */
#define NUMBER '0' /* SIGNAL THAT A NUMBER WAS FOUND */
#define MAXVAL 100
int gettop(char []);
void push(double);
double pop(void);
int sp = 0; /* Next free stack position. */
double val[MAXVAL];


//reverse Polish calulator
int main(void)
{
int type;
double op2;
char s[MAXOP];

while((type = getop(s)) != EOF)
{
switch(type)
{
case NUMBER:
push(atof(s));
break;
case '+':
push(pop() + pop());
break;
case '*':
push(pop() * pop());
break;

case '-':
op2=pop();
push(pop() - op2);
break;
case '-':
op2=pop();
if(op2 != 0.0)
push(pop() / op2);
else printf("nError: Zero divissorn");
break;
case '%':
op2 = pop();
if(op2)
push(fmod(pop(), op2));
else
printf("nError: Division by zero!");
break;
case 'n':
printf("t%.8gn",pop());
break;
default:
printf("error: unknown command %sn", s);
break;

}
}
return 0;
}




/* Getop: get next operator or numeric operand. */
int getop(char s[])
{

int i = 0;
int c;
int rc;
static char lastc[] = " ";
sscanf(lastc,"%c", &c);
lastc[0] = ' ';

/* Skip whitespace */
while((s[0] = c ) == ' ' || c == 't')
if(scanf("%",&c) == EOF)
c = EOF;
s[1] = '