C Program to find the even numbers square and sum from 1 to 10.

C Program to find the even numbers square and sum from 1 to 10.
Even number is an integer, which is the multiple of two. In this program we use the for loop to produce the even numbers. Try to change the for loop limits you can get the various range results. Read more about C Programming Language .
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#include<stdio.h>
#include<conio.h>
int main()
{
int i,j,sum = 0;
clrscr();
printf("nEven numbers and their squares from 1 to 10:n");
for(i =1; i <=10; i++)
{
if(i % 2 == 0)
{
j = i * i;
printf("%dtt%d",i,j);
printf("n");
sum = sum + j;
}
}
printf("nnSum of even numbers square from 1 to 10 is: %d",sum);
return 0;

}
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K & R C Programs Exercise 5-20.

K and R C, Solution to Exercise 5-20:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
C Program to expand dcl to handle declarations with function argument types, qualifiers like const, and so on. Read more about C Programming Language .
/***********************************************************
* You can use all the programs on www.c-program-example.com
* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact info@c-program-example.com
* To find more C programs, do visit www.c-program-example.com
* and browse!
*
* Happy Coding
***********************************************************/


#include<stdio.h>
#include<string.h>
#include<ctype.h>
enum { NAME, PARENS, BRACKETS};
enum { NO, YES};
void dcl(void);
void dirdcl(void);
void errmsg(char *);
void dclspec(void);
int typespec(void);
int typeequal(void);
int compare(char **, char**);
void parmdcl(void);

int gettoken(void);
extern int tokentype;
extern char token[];
extern char name[];
extern char datatype[];
extern char out[];
extern int prevtoken;


//dcl:parse a declarator
void dcl(void)
{
int ns;
for(ns = 0; gettoken() == '*';)
ns++;
dirdcl();
while(ns --> 0)
strcat(out, "pointer to");
}


//dirdcl: parse a direct declaration
void dirdcl(void)
{
int type;
void parmdcl(void);
if(tokentype == '('){
dcl();
if(tokentype != ')')
errmsg("error:missimg)n");
}
else if(tokentype == NAME){
if(name[0] == '