K & R C Programs Exercise 2-5.

Posted on December 30, 2011 by Sandeepa Nadahalli

K and R C, Solution to Exercise 2-5:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language, second addition, by Brian W.Keringhan and Dennis M.Ritchie(Prentice Hall,1988). You can learn and solve K&R C Programs Exercise.
Write the C function any(s1, s2), which returns the first location in the string s1 where any character from the string s2 occurs, or -1 if s1 contains no characters from s2.The standard library function strpbrk does the same job but returns a pointer to the location.Read more about C Programming Language .

/***********************************************************
* You can use all the programs on  www.c-program-example.com
* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact [email protected]
* To find more C programs, do visit www.c-program-example.com
* and browse!
* 
*                      Happy Coding
***********************************************************/

int any(char s1[], chars2[])
{
 int i, j;
 for(i=0;s1[i]!='';i++)

  for(j=0;s2[[j]!='' ;j++)

   if(s1[i]==s2[j])
    return i;

 return -1;
}

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K and R C Programs Exercise

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K & R C Programs Exercise 2-4.

Posted on December 30, 2011 by Sandeepa Nadahalli

K and R C, Solution to Exercise 2-4:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language, second addition, by Brian W.Keringhan and Dennis M.Ritchie(Prentice Hall,1988). You can learn and solve K&R C Programs Exercise.
Write an alternate version of squeeze(s1,s2) that deletes each character in s1 that matches any character in the string s2.
Compare ,First string with the second string, if any character matched, delete the matched character of the first string. Read more about C Programming Language .

/***********************************************************
* You can use all the programs on  www.c-program-example.com
* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact [email protected]
* To find more C programs, do visit www.c-program-example.com
* and browse!
* 
*                      Happy Coding
***********************************************************/


		/*squeeze: delete each char in s1 which is in s2*/
		void squeeze(char s1[], chars2[])
{
	int i, j, k;
	for(i=k=0;s1[i]!='';i++)
	{
		for(j=0;s2[[j]!='' && s2[j]!=s1[i];j++)
			;
		if(s2[j]=='')
			s1[k++]=s1[i];
	}
	s1[k]='';
}

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C Program to count the number of occurrences of particular word in a string

Posted on October 20, 2011June 25, 2017 by Sandeepa Nadahalli

C Program that counts the particular word in the given string. For example in the string ” the string is the set of charterers” , Number of occurrences of “the” is:2. Read more about C Programming Language .

/***********************************************************
* You can use all the programs on  www.c-program-example.com
* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact [email protected]
* To find more C programs, do visit www.c-program-example.com
* and browse!
* 
*                      Happy Coding
***********************************************************/

#include<stdio.h>

#include<string.h>

main()

{

 int strln,wordln,i,j,k,flag,count=0;

 char str[200],word[20];

 printf("Enter line of text:n");

 gets(str);

 printf("Enter the word to count:n");

 scanf("%s",word);

 strln=strlen(str);

 wordln=strlen(word);

 for(i=0;i<strln;i++)

 {

  if(str[i]==word[0]&&((str[i-1]==' '||i==0)&&(str[i+wordln]==' '||str[i+wordln]=='')))

  {

   for(flag=0,k=i+1,j=1;j<wordln;j++,k++)

   {

    if(str[k]==word[j])

    {

     flag++;

    }

   }

   if(flag==wordln-1)

   {

    count++;

   }

  }

 }

 printf("Number of occurence of '%s' = %dn",word,count);

}

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C Program to compare two strings

Posted on October 10, 2011June 25, 2017 by Sandeepa Nadahalli

C Strings:
C Program to accepts two strings and compare them, Finally it prints whether both are equal, or first string is greater than the second or the first string is less than the second string. The string comparison starts with the first character in each string and continues with subsequent characters until the corresponding characters differ or until the end of the strings is reached. Read more about C Programming Language .

/***********************************************************
* You can use all the programs on  www.c-program-example.com
* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact [email protected]
* To find more C programs, do visit www.c-program-example.com
* and browse!
* 
*                                  Happy Coding
***********************************************************/              
#include<stdio.h>
#include<conio.h>

void main()
{
 int count1=0,count2=0,flag=0,i;
 char str1[10],str2[10];

 clrscr();
 puts("Enter a string:");
 gets(str1);

 puts("Enter another string:");
 gets(str2);
 /*Count the number of characters in str1*/
 while (str1[count1]!='')
  count1++;
 /*Count the number of characters in str2*/
 while (str2[count2]!='')
  count2++;
 i=0;

 /*The string comparison starts with the first character in each string and
 continues with subsequent characters until the corresponding characters
 differ or until the end of the strings is reached.*/

 while ( (i < count1) && (i < count2))
 {
  if (str1[i] == str2[i])
  {
   i++;
   continue;
  }
  if (str1[i]<str2[i])
  {
   flag = -1;
   break;
  }
  if (str1[i] > str2[i])
  {
   flag = 1;
   break;
  }
 }

 if (flag==0)
  printf("Both strings are equaln");
 if (flag==1)
  printf("String1 is greater than string2n", str1, str2);
 if (flag == -1)
  printf("String1 is less than string2n", str1, str2);
 getch();
}

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C Program to implement strlen function

Posted on October 3, 2011 by Sandeepa Nadahalli

Write a c program to find the length of a string without using the built-in function strlen(). Program will calculate the length of the string using for loop by going through each character of the string, till its end. Read more about C Programming Language .

/***********************************************************
* You can use all the programs on  www.c-program-example.com
* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact [email protected]
* To find more C programs, do visit www.c-program-example.com
* and browse!
* 
*                      Happy Coding
***********************************************************/
#include <stdio.h>

void main()
{
 char string[50];
 int  i, length = 0;

 printf("Enter a stringn");
 gets(string);

 for (i=0; string[i] != ''; i++) /*keep going through each */
 {                                 /*character of the string */
  length++;                     /*till its end */
 }
 printf("The length of a string is the number of characters in itn");
 printf("So, the length of %s =%dn", string, length);
}

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C Program to accept a string and a substring and check if the substring is present in the given string

Posted on October 3, 2011 by Sandeepa Nadahalli

C Strings:
Write a C program to accept a string and a substring and check if the substring is present in the given string. Program search’s given substring is in the string or not, and prints the appropriate message. Read more about C Programming Language .

/***********************************************************
* You can use all the programs on  www.c-program-example.com
* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact [email protected]
* To find more C programs, do visit www.c-program-example.com
* and browse!
* 
*                         Happy Coding
***********************************************************/




#include<stdio.h>
#include<conio.h>

void main()
{
 char str[80],search[10]; 
 int count1=0,count2=0,i,j,flag;


 clrscr();

 puts("Enter a string:");
 gets(str);

 puts("Enter search substring:");
 gets(search);

 while (str[count1]!='')
  count1++;

 while (search[count2]!='')
  count2++;

 for(i=0;i<=count1-count2;i++)
 {
  for(j=i;j<i+count2;j++)
  {
   flag=1;
   if (str[j]!=search[j-i])
   {
    flag=0;
    break;
   }
  }
  if (flag==1)
   break;
 }
 if (flag==1)
  puts("SEARCH SUCCESSFUL!");
 else
  puts("SEARCH UNSUCCESSFUL!");
 getch();
}

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