C Program to add one to digits of a number

Write C Program to add one to digits of a number.
C Program that adds the 1 to each single digit of a number, i.e for Example 12345’s output is 23456.
If the digit is 9 it adds 1 and follows the carry system, 9 becomes 0 and 9’s left digit adds one more 1. I.e., 3491’s output is 4602. Read more about C Programming Language .

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#include<stdio.h>
#include<conio.h>
int main()
{
 int num, sum = 0;
 int rem, check = 0;
 clrscr( );
 printf("Enter the required number:");
 scanf("%d",&num);
 printf("nGiven Number: %d",num);
 while(num>0) 
 {
  rem = num % 10;
  if(rem != 9)
  {
   if(check == 0) 
    sum = (10 * sum) + (rem + 1);
   else{
    sum = (10*sum) + (rem + 2);
    check = 0;
   }
  } 
  else{
   sum = (10 * sum) + 0;
   check = 1;
  }
  num = num/10;
 } 

 num = sum; sum=0;
 while(num > 0)
 {
  rem = num % 10;
  sum = (10*sum) + rem;
  num = num / 10;
 }
 printf("nAfter Adding one: %d",sum);
 getch( );
 return 0;
}
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2 comments on “C Program to add one to digits of a number

  • Anonymous says:

    This program uses a user defined function ‘getSumOfDigit’ to find the sum of digits of a number.

    Reply
    • Sandeepa Nadahalli says:

      hey!
      I can’t see that function call here!

      Did you post the comment on a wrong program?

      Reply

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