C Program to find the subsets in the set. We use the backtracking method to solve this problem. Backtracking is the refinement method of Brute-Force method. Backtrack method means it finds the number of sub solutions and each may have number of sub divisions, and solution chosen for exactly one. Backtracking method is a recursive method. Read more about C Programming Language .

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#include<stdio.h>

#include<conio.h>

#define TRUE 1

#define FALSE 0

int inc[50],w[50],sum,n;

int promising(int i,int wt,int total)

{

return(((wt+total)>=sum)&&((wt==sum)||(wt+w[i+1]<=sum)));

}

/*

* You can find this program on GitHub

* https://github.com/snadahalli/cprograms/blob/master/subsets.c

*/

void main()

{

int i,j,n,temp,total=0;

clrscr();

printf("n Enter how many numbers:n");

scanf("%d",&n);

printf("n Enter %d numbers to th set:n",n);

for(i=0;i<n;i++)

{

scanf("%d",&w[i]);

total+=w[i];

}

printf("n Input the sum value to create sub set:n");

scanf("%d",&sum);

for(i=0;i<=n;i++)

for(j=0;j<n-1;j++)

if(w[j]>w[j+1])

{

temp=w[j];

w[j]=w[j+1];

w[j+1]=temp;

}

printf("n The given %d numbers in ascending order:n",n);

for(i=0;i<n;i++)

printf("%d t",w[i]);

if((total<sum))

printf("n Subset construction is not possible");

else

{

for(i=0;i<n;i++)

inc[i]=0;

printf("n The solution using backtracking is:n");

sumset(-1,0,total);

}

getch();

}

void sumset(int i,int wt,int total)

{

int j;

if(promising(i,wt,total))

{

if(wt==sum)

{

printf("n{t");

for(j=0;j<=i;j++)

if(inc[j])

printf("%dt",w[j]);

printf("}n");

}

else

{

inc[i+1]=TRUE;

sumset(i+1,wt+w[i+1],total-w[i+1]);

inc[i+1]=FALSE;

sumset(i+1,wt,total-w[i+1]);

}

}

}

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## 2 comments on “C program to create a subsets using backtracking method.”

awesome………. i have literally gone through the entire web… and finally i got it here

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