C Program to Demonstrate getting the parameters from the command line.

C Program to getting the parameters from the command line. To pass the arguments from command line, in main function we have to declare two arguments . First one is number of arguments passed to the program and other one is pointer variable which gives the list of arguments passed. Read more about C Programming Language .

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#include <stdio.h>

main(int argc, char *argv[]) {
int count;

/* Main takes two variables 'argc' is the number of parms on the
* command line and 'argv' is a pointer to each of the parameters.
* int argc -- integer number called 'argc'
* char *argv[] -- Character pointer array!

printf("%i parameters entered on the command line.n", argc);

* progname argc = 1
* progname parm1 parm2 argc = 3

* We take 1 from argc because
* the argv array starts at zero
* an ends at argc -1

for (count = 0; count <= argc - 1; count++) {
/* printf expects a pointer
* to the text

printf("parm %d is %sn", count, argv[count]);
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