C program which demonstrates the working of increment(++) and decrement(–) operators. Increment operator ++ adds 1 to its operand and Decrement operator — subtracts 1 from its operand.
These operators may be used either as a prefix operator or post-fix operator. Read more here: Increment and decrement operators
The Program
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
| /* C Program to demonstrate increment and decrement operators */ | |
| main() | |
| { | |
| /* | |
| * ++i -> i incremented before i is used. | |
| * --i -> i decremented before i is used. | |
| * j++ -> j is incremented AFTER j has been used. | |
| * j-- -> j is decremented AFTER j has been used. | |
| */ | |
| int i=1,j=1; | |
| puts("\tDemo 1"); | |
| printf("\t%d %d\n",++i, j++); /* O/P 2 1 */ | |
| printf("\t%d %d\n",i, j); /* O/P 2 2 */ | |
| i=1; j=1; | |
| puts("\n\tDemo 2"); | |
| printf("\t%d \n", i=j++); /* O/P 1 */ | |
| printf("\t%d \n", i=++j); /* O/P 3 */ | |
| i = 0; j = 0; | |
| puts("\n\tDemo 3"); | |
| if ( (i++ == 1) && (j++ == 1)) puts("Some text"); | |
| /* Will i and j get incremented? The answer is NO! Because | |
| * the expression in the left of '&&' resolves to false the | |
| * compiler does NOT execute the expression on the right and | |
| * so 'j' does not get executed!!!!! */ | |
| printf("\t%d %d\n",i, j); /* O/P 1 0 */ | |
| } |
Sample Output
Related programs
Airthmatic Operators
You can easily select the code by double clicking on the code area above.
To get regular updates on new C programs, you can Follow @c_program
You can discuss these programs on our Facebook Page.
Like to get updates right inside your feed reader? Grab our feed!
(c) www.c-program-example.com
2 comments on “C Program to Demonstrate the increment and decrement operators”
Awesome
Thanks Ashfa 🙂