K & R C Programs Exercise 3-6.

K and R C, Solution to Exercise 3-6:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
C program to change version of itoa that accepts three arguments instead of two(K and R C Exercise 3-4). The third argument is a minimum field width; the converted number must be paddle with blanks on the left if necessary to make it wide enough. Read more about C Programming Language .

`/************************************************************ You can use all the programs on  www.c-program-example.com* for personal and learning purposes. For permissions to use the* programs for commercial purposes,* contact [email protected]* To find more C programs, do visit www.c-program-example.com* and browse!* *                      Happy Coding***********************************************************/#include <stdlib.h>#include <stdio.h>#include <limits.h>#define abs(x)  ((x) < 0 ? -(x) : (x))void itoa(int n, char s[], int w);void reverse(char s[]);int main(void) { char buffer[20]; printf("INT_MIN: %dn", INT_MIN); itoa(INT_MIN, buffer); printf("Buffer : %sn", buffer); return 0;}//itoa: convert to n characters in s, w characters wide.void itoa(int n, char s[], int w){ void int i, sign; void everse(char s[]); sign = n; i = 0; do{  s[i++] = abs(n%10) + '0';  printf("%d %% %d + '0' = %dn", n, 10, s[i-1]); }while((n/=10)!=0); if(sign < 0)  s[i++] = '-'; while(i < w)  s[i++] = ' '; s[i] = ''; reverse(s);}void reverse(char s[]) { int c, i, j; for ( i = 0, j = strlen(s)-1; i < j; i++, j--) {  c = s[i];  s[i] = s[j];  s[j] = c; }}`
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