C Program which produces its own source code as its output.

Write a c program which produces its own source code as its output.
This C program uses the C File i/o operations like fopen(), fclose(). In this program, We pritn the source code of the program.Read more about C Programming Language .
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* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact info@c-program-example.com
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* and browse!
*
* Happy Coding
***********************************************************/

#include<stdio.h>
int main()
{
FILE *fp;
char c;

fp = fopen(__FILE__,"r");

do{

c= getc(fp);

putchar(c);

}
while(c!=EOF);

fclose(fp);

return 0;

}


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C Basic

C File i/o

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C Program to print ASCII values of all characters.

C Program to print ASCII values of all characters.
ASCII value is the American Standard Code for Information Interchange.
ASCII value is the numerical value, or order, of an character. There are 128 standard ASCII characters, numbered from 0 to 127. Extended ASCII adds another 128 values and goes to 255. The numbers are typically represented in decimal or in hexadecimal. Read more about C Programming Language .
/***********************************************************
* You can use all the programs on www.c-program-example.com
* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact info@c-program-example.com
* To find more C programs, do visit www.c-program-example.com
* and browse!
*
* Happy Coding
***********************************************************/

#include<stdio.h>
#include<conio.h>
int main(){

int i;
clrscr();
for(i=0;i<=255;i++)
printf("ASCII value of
character %c: %dn",i,i);
getch();
return 0;

}
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Number System

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C Program to find the strong number.

Write a C Program to find the given number is strong or not?
A number is called strong number if sum of the factorial of its digit is equal to number itself.
Example: 145 since 1! + 4! + 5! = 1 + 24 + 120 = 145.
Read more about C Programming Language .
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* You can use all the programs on www.c-program-example.com
* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact info@c-program-example.com
* To find more C programs, do visit www.c-program-example.com
* and browse!
*
* Happy Coding
***********************************************************/
#include<stdio.h>
#include<conio.h>

int main()
{
int num,i,f,r,sum=0,num1;
clrscr();
printf("Enter a number: ");
scanf("%d",&num);

num1=num;
while(num){
i=1,f=1;
r=num%10;

while(i<=r){
f=f*i;
i++;
}
sum=sum+f;
num=num/10;

}
if(sum==num1)
printf("%d is a strong number",num1);
else
printf("%d is not a strong number",num1);
getch();
return 0;

}
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Number System

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C Program to find the two sets Intersection and Union

Write a C Program to find the two sets Intersection and Union
A Set is a collection of well defined and distinct objects.
Intersection of two sets A and B is defined as, all the elements of set A, which are also elements of set B.Union of two sets A and B is defined as, all the elements of A and B, but not belonged to both.
Read more about C Programming Language .
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* programs for commercial purposes,
* contact info@c-program-example.com
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* and browse!
*
* Happy Coding
***********************************************************/

#include<stdio.h>
#include<conio.h>
void Union(int set1[10],int set2[10],int m,int n);
void Intersection(int set1[10],int set2[10],int m,int n);
void main()
{
int a[10],b[10],m,n,i,j;
int ch;
clrscr();
printf("nEnter the number of elements in first set:n");
scanf("%d",&m);
printf("nEnter the elements:n");
for(i=0;i<m;i++)
{
scanf("%d",&a[i]);
}
printf("nElement of First set:nn");
for(i=0;i<m;i++)
{
printf("%dt",a[i]);
}
printf("nEnter the number of elements in second set:n");
scanf("%d",&n);
printf("nEnter the elements:n");
for(i=0;i<n;i++)
{
scanf("%d",&b[i]);
}
printf("nElement of second setn");
for(i=0;i<n;i++)
{
printf("%dt",b[i]);
}
for(;;)
{
printf("nnMenunn1.Unionn2.Intersection");
printf("n3.exit");
printf("nEnter your choice:n");
scanf("%d",&ch);
switch(ch) {
case 1:
Union(a,b,m,n);
break;
case 2:
Intersection(a,b,m,n);
break;
case 3:
exit(0);
}
getch();
}
}

void Union(int a[10],int b[10],int m,int n)
{
int c[20],i,j,k=0,flag=0;
for(i=0;i<m;i++)
{
c[k]=a[i];
k++;
}
for(i=0;i<n;i++)
{
flag=0;
for(j=0;j<m;j++)
{
if(b[i]==c[j])
{
flag=1;
break;
}
}
if(flag==0)
{
c[k]=b[i];
k++;
}
}
printf("nElement of resultant setnn");
for(i=0;i<k;i++)
{
printf("t%d",c[i]);
}
}
void Intersection(int a[10],int b[10],int m,int n)
{
int c[20],i,j,k=0,flag=0;
for(i=0;i<m;i++)
{
flag=0;
for(j=0;j<n;j++)
{
if(a[i]==b[j])
{
flag=1;
break;
}
}
if(flag==1)
{
c[k]=a[i];
k++;
}
}
if(k==0)
{
printf("nnResultant set is null set!n");
}else{
printf("nElement of resultant setn");
for(i=0;i<k;i++)
{
printf("t%d",c[i]);
}
}
}


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K & R C Programs Exercise 4-8.

K and R C, Solution to Exercise 4-8:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
C Program to modify the K & R C Programs Exercise 4-7, Suppose there will never be more than one character of pushback. Modify getch and ungetch accordingly. Read more about C Programming Language .
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* 
*                      Happy Coding
***********************************************************/

#include <stdio.h>
char buf = 0;

//getch: get a (possible pushed character back) character
int getch(void)
{
 int c;
 if(buf != 0)
  c = buf;
 else
  c getchar();
 buf = =0;
 return c;
}

/*ungetch: push string back onto the input*/
void ungetch(int c)
{
 if (buf != 0)
  printf("ungetch: too many characters!n");
 else
  buf = c;
}
int main(void)
{
 int c;

 while ((c = getch()) != EOF) {
  if (c == '/') {
   putchar(c);
   if ((c = getch()) == '*') { 
    ungetch('!');
   }         
  } 
  putchar(c);               
 }
 return 0;
}
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K & R C Programs Exercise 4-7.

K and R C, Solution to Exercise 4-7:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
Write C program that will push back an entire string onto the the input.
ungets calls the routine ungetch len times, each time pushing back a character from the string s onto the input. ungets pushes the string back in reverse order.
The routine ungets does not need to worried about the buf and bufp. The routine ungetch handles buf, bufp, and error handling. Read more about C Programming Language .
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* and browse!
*
* Happy Coding
***********************************************************/

#include<stdio.h>
/*ungets: push string back onto the input*/

void ungets(char s[])
{
int len=strlen(s);
void ungetch(int);
while (len >0)
ungetch(s[--len]);
}
int main(void)
{
char *s = "oh! this is for testing!";
int c;

ungets(s);
while ((c = getch()) != EOF)
putchar(c);
return 0;
}
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K & R C Programs Exercise 4-6.

K and R C, Solution to Exercise 4-6:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
C Program to Add commands for handling variables.(It’s easy to provide twenty-six variables with single-letter names.). Add a variable for the most recently printed value.
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* programs for commercial purposes,
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*
* Happy Coding
***********************************************************/

#include <stdlib.h>
#include <stdio.h>
#include <ctype.h>
#include <math.h>
#include <string.h>

#define MAXOP 100
#define NUMBER 0
#define IDENTIFIER 1
#define ENDSTRING 2
#define TRUE 1
#define FALSE 0
#define MAX_ID_LEN 32
#define MAXVARS 30


struct varType{
char name[MAX_ID_LEN];
double val;
};


int Getop(char s[]);
void push(double val);
double pop(void);
void showTop(void);
void duplicate(void);
void swapItems(void);
void clearStacks(struct varType var[]);
void dealWithName(char s[], struct varType var[]);
void dealWithVar(char s[], struct varType var[]);

int pos = 0;
struct varType last;

int main(void)
{
int type;
double op2;
char s[MAXOP];
struct varType var[MAXVARS];

clearStacks(var);

while((type = Getop(s)) != EOF)
{
switch(type)
{
case NUMBER:
push(atof(s));
break;
case IDENTIFIER:
dealWithName(s, var);
break;
case '+':
push(pop() + pop());
break;
case '*':
push(pop() * pop());
break;
case '-':
op2 = pop();
push(pop()- op2);
break;
case '/':
op2 = pop();
if(op2)
push(pop() / op2);
else
printf("nError: division by zero!");
break;
case '%':
op2 = pop();
if(op2)
push(fmod(pop(), op2));
else
printf("nError: division by zero!");
break;
case '?':
showTop();
break;
case '#':
duplicate();
break;
case '~':
swapItems();
break;
case '!':
clearStacks(var);
break;
case 'n':
printf("nt%.8gn", pop());
break;
case ENDSTRING:
break;
case '=':
pop();
var[pos].val = pop();
last.val = var[pos].val;
push(last.val);
break;
case '<':
printf("The last variable used was: %s (value == %g)n",
last.name, last.val);
break;

default:
printf("nError: unknown command %s.n", s);
break;
}
}
return EXIT_SUCCESS;
}

#define MAXVAL 100

int sp = 0;
double val[MAXVAL];

/* push: push f onto stack. */
void push(double f)
{
if(sp < MAXVAL)
val[sp++] = f;
else
printf("nError: stack full can't push %gn", f);
}

/*pop: pop and return top value from stack.*/
double pop(void)
{
if(sp > 0)
{
return val[--sp];
}
else
{
printf("nError: stack emptyn");
return 0.0;
}
}

void showTop(void)
{
if(sp > 0)
printf("Top of stack contains: %8gn", val[sp-1]);
else
printf("The stack is empty!n");
}


void duplicate(void)
{
double temp = pop();

push(temp);
push(temp);
}

void swapItems(void)
{
double item1 = pop();
double item2 = pop();

push(item1);
push(item2);
}


void clearStacks(struct varType var[])
{
int i;
sp = 0;

for( i = 0; i < MAXVARS; ++i)
{
var[i].name[0] = '