C program is one of most popular programming language which is used for core level of coding across the board. C program is used for operating systems, embedded systems, system engineering, word processors,hard ware drivers, etc.
In this site, we have discussed various type of C programs till date and from now on, we will move further by looking at the C aptitude questions.
In the coming days, we will post C aptitude questions, answers and explanation for interview preparations.
The C aptitude questions and answers for those questions along with explanation for the interview related queries.
We hope that this questions and answers series on C program will help students and freshers who are looking for a job, and also programmers who are looking to update their aptitude on C program.
Some of the illustrated examples will be from the various companies, and IT industry experts.
Read more about C Programming Language . and read the C Programming Language (2nd Edition). by K and R.
C aptitude 8.1
main()
{
char *p="hai friends",*p1;
p1=p;
while(*p!=' ') ++*p++;
printf("%s %s",p,p1);
}
Answer:ibj!gsjfoet
Explanation: ++*p++ will be parse in the given order Ø *p that is value at the location currently pointed by p will be taken Ø ++*p the retrieved value will be incremented Ø when ; is encountered the location will be incremented that is p++ will be executed Hence, in the while loop initial value pointed by p is ‘h’, which is changed to ‘i’ by executing ++*p and pointer moves to point, ‘a’ which is similarly changed to ‘b’ and so on. Similarly blank space is converted to ‘!’. Thus, we obtain value in p becomes “ibj!gsjfoet” and since p reaches ‘ ’ and p1 points to p thus p1doesnot print anything.
C aptitude 8.2
#define a 10
main()
{
#define a 50
printf("%d",a);
}
Answer:50
Explanation:The preprocessor directives can be redefined anywhere in the program. So the most recently assigned value will be taken.
C aptitude 8.3
#define clrscr() 100
main()
{
clrscr();
printf("%dn",clrscr());
}
Answer:100
Explanation: Preprocessor executes as a seperate pass before the execution of the compiler. So textual replacement of clrscr() to 100 occurs.The input program to compiler looks like this :
main()
{
100;
printf(“%dn”,100);
}
Note: 100; is an executable statement but with no action. So it doesn’t give any problem
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