C program is one of most popular programming language which is used for core level of coding across the board. C program is used for operating systems, embedded systems, system engineering, word processors,hard ware drivers, etc.
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In the coming days, we will post C aptitude questions, answers and explanation for interview preparations.
The C aptitude questions and answers for those questions along with explanation for the interview related queries.
We hope that this questions and answers series on C program will help students and freshers who are looking for a job, and also programmers who are looking to update their aptitude on C program.
Some of the illustrated examples will be from the various companies, and IT industry experts.
Read more about C Programming Language . and read the C Programming Language (2nd Edition). by K and R.
C aptitude 5.1
#define int char
main()
{
int i=65;
printf("sizeof(i)=%d",sizeof(i));
}
Answer: sizeof(i)=1
Explanation: Since the #define replaces the string int by the macro char
C aptitude 5.2
main()
{
int i=10;
i=!i>14;
Printf ("i=%d",i);
}
Answer:i=0
Explanation:In the expression !i>14 , NOT (!) operator has more precedence than ‘ >’ symbol. ! is a unary logical operator. !i (!10) is 0 (not of true is false). 0>14 is false (zero).
C aptitude 5.3
#include
main()
{
char s[]={'a','b','c','n','c',' '};
char *p,*str,*str1;
p=&s[3];
str=p;
str1=s;
printf("%d",++*p + ++*str1-32);
}
Answer:77
Explanation: p is pointing to character ‘n’. str1 is pointing to character ‘a’ ++*p. “p is pointing to ‘n’ and that is incremented by one.” the ASCII value of ‘n’ is 10, which is then incremented to 11. The value of ++*p is 11. ++*str1, str1 is pointing to ‘a’ that is incremented by 1 and it becomes ‘b’. ASCII value of ‘b’ is 98. Now performing (11 + 98 – 32), we get 77(“M”); So we get the output 77 :: “M” (Ascii is 77).
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