C Aptitude Questions and answers with explanation

C Aptitude 23
C program is one of most popular programming language which is used for core level of coding across the board. C program is used for operating systems, embedded systems, system engineering, word processors,hard ware drivers, etc.

In this site, we have discussed various type of C programs till date and from now on, we will move further by looking at the C aptitude questions.

The C aptitude questions and answers for those questions along with explanation for the interview related queries.

We hope that this questions and answers series on C program will help students and freshers who are looking for a job, and also programmers who are looking to update their aptitude on C program.
Some of the illustrated examples will be from the various companies, and IT industry experts.
Read more about how to prepare and write the C Aptitude Exams?
Read more about C Programming Language . and read the C Programming Language (2nd Edition). by K and R.

 

Predict the output or error(s) for the following:

C aptitude 23.1

void main(){
int res;
res= 56>76 ? return 0:return 1;
printf("%d",res);
}

Answer: Compilation error.

Explanation: We cannot use return keyword in conditional operator.

C aptitude 23.2
Note: here input for command line argument is, example 5 4 7 8

 
/* example.c */
#include

int main(int argc, char *argv[])
{
int j;
j = argv[1] + argv[2] + argv[3] + argv[4];
printf("%d", j);
return 0;
}

Answer: Error

Explanation: Command line arguments are string types, we can’t add or do the arithmetic operations on string types in C, we have to convert the argv[] to the integer types using atoi function.

C aptitude 23.3

     int main()
{
int num1 = 123;
float num2 = 123.0;
if(num1 == num2)
printf("num1 and num2 are equal");
else
printf("num1 and num2 are not equal");
return 0;
}

Answer: num1 and num2 are equal

Explanation: This is the tricky question, in if statement we are comparing 123=123.0, condition satisfied, so the result is num1 and num2 are equal.

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