Binary To Decimal in C

C Program to convert a binary number into its equivalent Decimal. In binary number system or base-2 system numeric valuer are represented by using two different symbols 0 and 1. The binary number system is a positional notation with a radix of 2.

Read more here: What are binary, octal, and hexadecimal notation?

This program converts a given base-2 number to it’s decimal equivalent (or base-10 representation).

The Program

#include<stdio.h>
/*
* Function to convert a given binary number to
* its decimal equivalent.
*/
int binary_to_decimal(int num) {
int rem, base = 1, decimal_number = 0;
while( num > 0) {
rem = num % 10;
if((rem == 0) || (rem == 1)) {
decimal_number = decimal_number + rem * base;
num = num / 10 ;
base = base * 2;
} else {
return -1; // Invalid binary number
}
}
return decimal_number;
}
int main() {
long int binary_number, decimal_number;
printf("Enter any binary number : ");
scanf("%ld", &binary_number);
decimal_number = binary_to_decimal(binary_number);
if(decimal_number != -1) {
printf("The decimal equivalent value of binary %ld is: %ld",
binary_number, decimal_number);
} else {
printf("\nPlease enter a valid binary number!");
}
return 0;
}

Sample Output

Binary To Decimal

 

Related Programs

Edit1: 21st August 2017

  • Added links to related programs
  • Added a screenshot of sample output
  • Moved program to it’s own gist.

 

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C Program to convert a given decimal number into its binary equivalent

C Program to convert a given decimal number into its binary equivalent. In this program we convert the given decimal based number system(0, 1, 2, 3, —–,9) to Binary number system(0 and 1). Read more about C Programming Language .

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* Happy Coding
***********************************************************/
/* Write a program to convert a given decimal numbers into its binary equivalent . */
#include<stdio.h>
int main()
{
int num,i=0,binary=0,num1, biny[30],counter=0;
printf("Enter the Decimal number:\n");
scanf("%d",&num);
num1=num;
do
{
binary=num%2;
biny[i]=binary;
num=num/2;
i++;
counter++;
} while(num>0);
printf("\nThe given decimal %d number binary equalant is :\n",num1);
counter--;
while(counter>=0){
printf("%d" ,biny[counter]);
counter--;
}
return 0;
}

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