C Program to find the two sets Intersection and Union

Write a C Program to find the two sets Intersection and Union
A Set is a collection of well defined and distinct objects.
Intersection of two sets A and B is defined as, all the elements of set A, which are also elements of set B.Union of two sets A and B is defined as, all the elements of A and B, but not belonged to both.
Read more about C Programming Language .
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#include<stdio.h>
#include<conio.h>
void Union(int set1[10],int set2[10],int m,int n);
void Intersection(int set1[10],int set2[10],int m,int n);
void main()
{
int a[10],b[10],m,n,i,j;
int ch;
clrscr();
printf("nEnter the number of elements in first set:n");
scanf("%d",&m);
printf("nEnter the elements:n");
for(i=0;i<m;i++)
{
scanf("%d",&a[i]);
}
printf("nElement of First set:nn");
for(i=0;i<m;i++)
{
printf("%dt",a[i]);
}
printf("nEnter the number of elements in second set:n");
scanf("%d",&n);
printf("nEnter the elements:n");
for(i=0;i<n;i++)
{
scanf("%d",&b[i]);
}
printf("nElement of second setn");
for(i=0;i<n;i++)
{
printf("%dt",b[i]);
}
for(;;)
{
printf("nnMenunn1.Unionn2.Intersection");
printf("n3.exit");
printf("nEnter your choice:n");
scanf("%d",&ch);
switch(ch) {
case 1:
Union(a,b,m,n);
break;
case 2:
Intersection(a,b,m,n);
break;
case 3:
exit(0);
}
getch();
}
}

void Union(int a[10],int b[10],int m,int n)
{
int c[20],i,j,k=0,flag=0;
for(i=0;i<m;i++)
{
c[k]=a[i];
k++;
}
for(i=0;i<n;i++)
{
flag=0;
for(j=0;j<m;j++)
{
if(b[i]==c[j])
{
flag=1;
break;
}
}
if(flag==0)
{
c[k]=b[i];
k++;
}
}
printf("nElement of resultant setnn");
for(i=0;i<k;i++)
{
printf("t%d",c[i]);
}
}
void Intersection(int a[10],int b[10],int m,int n)
{
int c[20],i,j,k=0,flag=0;
for(i=0;i<m;i++)
{
flag=0;
for(j=0;j<n;j++)
{
if(a[i]==b[j])
{
flag=1;
break;
}
}
if(flag==1)
{
c[k]=a[i];
k++;
}
}
if(k==0)
{
printf("nnResultant set is null set!n");
}else{
printf("nElement of resultant setn");
for(i=0;i<k;i++)
{
printf("t%d",c[i]);
}
}
}


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K & R C Programs Exercise 4-8.

K and R C, Solution to Exercise 4-8:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
C Program to modify the K & R C Programs Exercise 4-7, Suppose there will never be more than one character of pushback. Modify getch and ungetch accordingly. Read more about C Programming Language .
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* 
*                      Happy Coding
***********************************************************/

#include <stdio.h>
char buf = 0;

//getch: get a (possible pushed character back) character
int getch(void)
{
 int c;
 if(buf != 0)
  c = buf;
 else
  c getchar();
 buf = =0;
 return c;
}

/*ungetch: push string back onto the input*/
void ungetch(int c)
{
 if (buf != 0)
  printf("ungetch: too many characters!n");
 else
  buf = c;
}
int main(void)
{
 int c;

 while ((c = getch()) != EOF) {
  if (c == '/') {
   putchar(c);
   if ((c = getch()) == '*') { 
    ungetch('!');
   }         
  } 
  putchar(c);               
 }
 return 0;
}
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C Program to add one to digits of a number

Write C Program to add one to digits of a number.
C Program that adds the 1 to each single digit of a number, i.e for Example 12345’s output is 23456.
If the digit is 9 it adds 1 and follows the carry system, 9 becomes 0 and 9’s left digit adds one more 1. I.e., 3491’s output is 4602. Read more about C Programming Language .
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* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact info@c-program-example.com
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* and browse!
* 
*                      Happy Coding
***********************************************************/

#include<stdio.h>
#include<conio.h>
int main()
{
 int num, sum = 0;
 int rem, check = 0;
 clrscr( );
 printf("Enter the required number:");
 scanf("%d",&num);
 printf("nGiven Number: %d",num);
 while(num>0) 
 {
  rem = num % 10;
  if(rem != 9)
  {
   if(check == 0) 
    sum = (10 * sum) + (rem + 1);
   else{
    sum = (10*sum) + (rem + 2);
    check = 0;
   }
  } 
  else{
   sum = (10 * sum) + 0;
   check = 1;
  }
  num = num/10;
 } 

 num = sum; sum=0;
 while(num > 0)
 {
  rem = num % 10;
  sum = (10*sum) + rem;
  num = num / 10;
 }
 printf("nAfter Adding one: %d",sum);
 getch( );
 return 0;
}
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C program to implement bit flipping.

Write a C program to implement bit flipping.
C Program to setbits(x,p,n,y) that returns x with the n bits that begin at position p set to the rightmost n bits of y, leaving the other bits unchanged in the least number of lines.
Bit flipping or flip bit is the complement(~) of bits. i.e., 0 to 1 and vise versa. bit flipping is the bits manipulation or processing individual bits within a byte. Bit flipping is used in the very low-level programming and is often used in graphics and systems programming.Read more about C Programming Language .
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* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact info@c-program-example.com
* To find more C programs, do visit www.c-program-example.com
* and browse!
*
* Happy Coding
***********************************************************/

#include <stdio.h>
#include <math.h>
#include <limits.h>

unsigned setbits(unsigned x, unsigned p, unsigned n, unsigned y) {
x |= (y & ~(~0 << n)) << p;
size_t s = (int)(log(INT_MAX)/log(2)) + 1;
printf("nnnSuccess! Number after bit flipping: n", s);
int mask = pow(2.0, (int)s);
do {
((x & mask) == 0) ? printf("0") : printf("1");
((s%4)==0) ? printf(" ") : printf("");
x <<= 1;
} while (s--);
printf("n");
}


void main( ) {
unsigned retrn=1, begin=0, nbits=0, num=0;

printf("Enter the number to bit flip!n");
scanf("%d",&num);
printf("Enter the number of bits to be flip!n");
scanf("%d",&nbits);
printf("Enter the position to begin bit flip!n");
scanf("%d",&begin);
unsigned x = setbits(retrn, begin, nbits, num);

}
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C Program to print factors of the number.

Write a C Program to print factors of a number. Factors of a whole number are the whole numbers which are exactly divides the number. i.e reminder is equal to zero.
Example: Factors of 8 are: 1, 2, 4, and 8.
Read more about C Programming Language .
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* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact info@c-program-example.com
* To find more C programs, do visit www.c-program-example.com
* and browse!
*
* Happy Coding
***********************************************************/

#include<stdio.h>
#include<conio.h>
{
void main( )
{
int num,x;
clrscr( );
printf("Enter the required number:");
scanf("%d",&num);
printf("nThe factors are:");
for(x=1; x<=num; x++)
{
if(num%x==0)
printf("n%d",x);
}
getch( );
}
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K & R C Programs Exercise 3-6.

K and R C, Solution to Exercise 3-6:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
C program to change version of itoa that accepts three arguments instead of two(K and R C Exercise 3-4). The third argument is a minimum field width; the converted number must be paddle with blanks on the left if necessary to make it wide enough. Read more about C Programming Language .
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* for personal and learning purposes. For permissions to use the
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* contact info@c-program-example.com
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* and browse!
*
* Happy Coding
***********************************************************/

#include <stdlib.h>
#include <stdio.h>
#include <limits.h>
#define abs(x) ((x) < 0 ? -(x) : (x))
void itoa(int n, char s[], int w);
void reverse(char s[]);

int main(void) {
char buffer[20];

printf("INT_MIN: %dn", INT_MIN);
itoa(INT_MIN, buffer);
printf("Buffer : %sn", buffer);

return 0;
}
//itoa: convert to n characters in s, w characters wide.
void itoa(int n, char s[], int w)
{
void int i, sign;
void everse(char s[]);
sign = n;
i = 0;
do{
s[i++] = abs(n%10) + '0';
printf("%d %% %d + '0' = %dn", n, 10, s[i-1]);
}while((n/=10)!=0);
if(sign < 0)
s[i++] = '-';
while(i < w)
s[i++] = ' ';
s[i] = '