greedy algorithm Archives - C Program Examples

Write a C Program implement Kruskal’s algorithm.
Kruskal’s algorithm is a greedy algorithm that finds the minimum spanning tree of a graph. Graph should be weighted, connected, and undirected.Minimum spanning tree is a spanning tree with weight less than or equal to the weight of every other spanning tree. Read more about C Programming Language .

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#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
int i,j,k,a,b,u,v,n,ne=1;
int min,mincost=0,cost[9][9],parent[9];
int find(int);
int uni(int,int);
void main()
{
 clrscr();
 printf("nntImplementation of Kruskal's algorithmnn");
 printf("nEnter the no. of verticesn");
 scanf("%d",&n);
 printf("nEnter the cost adjacency matrixn");
 for(i=1;i<=n;i++)
 {
  for(j=1;j<=n;j++)
  {
   scanf("%d",&cost[i][j]);
   if(cost[i][j]==0)
    cost[i][j]=999;
  }
 }
 printf("nThe edges of Minimum Cost Spanning Tree arenn");
 while(ne<n)
 {
  for(i=1,min=999;i<=n;i++)
  {
   for(j=1;j<=n;j++)
   {
    if(cost[i][j]<min)
    {
     min=cost[i][j];
     a=u=i;
     b=v=j;
    }
   }
  }
  u=find(u);
  v=find(v);
  if(uni(u,v))
  {
   printf("n%d edge (%d,%d) =%dn",ne++,a,b,min);
   mincost +=min;
  }
  cost[a][b]=cost[b][a]=999;
 }
 printf("ntMinimum cost = %dn",mincost);
 getch();
}
int find(int i)
{
 while(parent[i])
  i=parent[i];
 return i;
}
int uni(int i,int j)
{
 if(i!=j)
 {
  parent[j]=i;
  return 1;
 }
 return 0;
}

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/***********************************************************
* You can use all the programs on www.c-program-example.com
* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact [email protected]
* To find more C programs, do visit www.c-program-example.com
* and browse!
*
* Happy Coding
***********************************************************/

#include "stdio.h"
#include "conio.h"
#define infinity 999

void dij(int n,int v,int cost[10][10],int dist[])
{
int i,u,count,w,flag[10],min;
for(i=1;i<=n;i++)
flag[i]=0,dist[i]=cost[v][i];
count=2;
while(count<=n)
{
min=99;
for(w=1;w<=n;w++)
if(dist[w]<min && !flag[w])
min=dist[w],u=w;
flag[u]=1;
count++;
for(w=1;w<=n;w++)
if((dist[u]+cost[u][w]<dist[w]) && !flag[w])
dist[w]=dist[u]+cost[u][w];
}
}

void main()
{
int n,v,i,j,cost[10][10],dist[10];
clrscr();
printf("n Enter the number of nodes:");
scanf("%d",&n);
printf("n Enter the cost matrix:n");
for(i=1;i<=n;i++)
for(j=1;j<=n;j++)
{
scanf("%d",&cost[i][j]);
if(cost[i][j]==0)
cost[i][j]=infinity;
}
printf("n Enter the source matrix:");
scanf("%d",&v);
dij(n,v,cost,dist);
printf("n Shortest path:n");
for(i=1;i<=n;i++)
if(i!=v)
printf("%d->%d,cost=%dn",v,i,dist[i]);
getch();
}