K & R C Programs Exercise 3-2.

K and R C, Solution to Exercise 3-2:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
C Program that converts the characters like newline and tab into visible escape sequences like n and t as it copies the string t to s. Use a Switch case, and Write the function for the other direction as well, converting escape sequences into the real characters. Read more about C Programming Language .

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#include <stdio.h>

void escape(char * s, char * t);
void unescape(char * s, char * t);

int main(void) {
char text1[50] = "aHello,ntWorld! Mistakeeb was "Extra 'e'"!n";
char text2[51];

printf("Original string:n%sn", text1);

escape(text2, text1);
printf("Escaped string:n%sn", text2);

unescape(text1, text2);
printf("Unescaped string:n%sn", text1);

return 0;
}

/*escape: expand newline and tab and others tabs into visible sequences using switch*/

void escape(char * s, char * t) {
int i, j;
i = j = 0;

while ( t[i] ) {



switch( t[i] ) {
case 'n':
s[j++] = '\';
s[j] = 'n';
break;

case 't':
s[j++] = '\';
s[j] = 't';
break;

case 'a':
s[j++] = '\';
s[j] = 'a';
break;

case 'b':
s[j++] = '\';
s[j] = 'b';
break;

case 'f':
s[j++] = '\';
s[j] = 'f';
break;

case 'r':
s[j++] = '\';
s[j] = 'r';
break;

case 'v':
s[j++] = '\';
s[j] = 'v';
break;

case '\':
s[j++] = '\';
s[j] = '\';
break;

case '"':
s[j++] = '\';
s[j] = '"';
break;

default:



s[j] = t[i];
break;
}
++i;
++j;
}
s[j] = t[i];
}


/* unescape: convert escape sequences into real charecters while copying the string t to s */

void unescape(char * s, char * t) {
int i, j;
i = j = 0;

while ( t[i] ) {
switch ( t[i] ) {
case '\':


switch( t[++i] ) {
case 'n':
s[j] = 'n';
break;

case 't':
s[j] = 't';
break;

case 'a':
s[j] = 'a';
break;

case 'b':
s[j] = 'b';
break;

case 'f':
s[j] = 'f';
break;

case 'r':
s[j] = 'r';
break;

case 'v':
s[j] = 'v';
break;

case '\':
s[j] = '\';
break;

case '"':
s[j] = '"';
break;

default:



s[j++] = '\';
s[j] = t[i];
}
break;

default:



s[j] = t[i];
}
++i;
++j;
}
s[j] = t[i];
}


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