C program is one of most popular programming language which used for core level of coding across the board. Now a days C program is used for operating systems, embedded systems, system engineering, word processors,hard ware drivers, etc.
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In the coming days, we will post C aptitude questions, answers and explanation for interview preparations.
The C aptitude questions and answers for those questions along with explanation for the interview related queries.
We hope that this questions and answers series on C program will help students and freshers who are looking for a job, and also programmers who are looking to update their aptitude on C program. Some of the illustrated examples will be from the various companies, and IT industry experts.
Read more about C Programming Language . and read the C Programming Language (2nd Edition). by K and R.
C aptitude 3.1
printf("%d %d %d %d %d",i,j,k,l,m);
Answer: 0 0 1 3 1
Explanation:Logical operations always give a result of 1 or 0 . And also the logical AND (&&) operator has higher priority over the logical OR (||) operator. So the expression ‘i++ && j++ && k++’ is executed first. The result of this expression is 0 (-1 && -1 && 0 = 0). Now the expression is 0 || 2 which evaluates to 1 (because OR operator always gives 1 except for ‘0 || 0’ combination- for which it gives 0). So the value of m is 1. The values of other variables are also incremented by 1.
C aptitude 3.2
printf("%d %d ",sizeof(*p),sizeof(p));
Explanation:The sizeof() operator gives the number of bytes taken by its operand. P is a character pointer, which needs one byte for storing its value (a character). Hence sizeof(*p) gives a value of 1. Since it needs two bytes to store the address of the character pointer sizeof(p) gives 2.
C aptitude 3.3
case 1: printf("one");
case 3: printf("three");
Explanation: The default case can be placed anywhere inside the loop. It is executed only when all other cases doesn’t match.
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