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The C aptitude questions and answers for those questions along with explanation for the interview related queries.
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Read more about C Programming Language . and read the C Programming Language (2nd Edition). by K and R.
Predict the output or error(s) for the following:
C aptitude 13.1
ain()
{
int i=0;
for(;i++;printf("%d",i)) ;
printf("%d",i);
}
Answer: 1
Explanation: before entering into the for loop the checking condition is “evaluated”. Here it evaluates to 0 (false) and comes out of the loop, and i is incremented (note the semicolon after the for loop).
C aptitude 13.2
main()
{
char s[]={'a','b','c','n','c',' '};
char *p,*str,*str1;
p=&s[3];
str=p;
str1=s;
printf("%d",++*p + ++*str1-32);
}
Answer: M
Explanation:p is pointing to character ‘n’.str1 is pointing to character ‘a’ ++*p meAnswer:”p is pointing to ‘n’ and that is incremented by one.” the ASCII value of ‘n’ is 10. then it is incremented to 11. the value of ++*p is 11. ++*str1 meAnswer:”str1 is pointing to ‘a’ that is incremented by 1 and it becomes ‘b’. ASCII value of ‘b’ is 98. both 11 and 98 is added and result is subtracted from 32. i.e. (11+98-32)=77(“M”);
C aptitude 13.3
main()
{
struct xx
{
int x=3;
char name[]="hello";
};
struct xx *s=malloc(sizeof(struct xx));
printf("%d",s->x);
printf("%s",s->name);
}
Answer: Compiler Error
Explanation: Initialization should not be done for structure members inside the structure declaration.
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