K & R C Programs Exercise 6-6.

K and R C, Solution to Exercise 6-6:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
C Program to implement a simple version of the #define processor(i.e , no arguments) suitable for use with C programs, based on the routines of this section, You may also find getch and ungetch helpful.Read more about C Programming Language .

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* for personal and learning purposes. For permissions to use the
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*
* Happy Coding
***********************************************************/

#include<stdio.h>
#include<ctype.h>
#include<string.h>

#define MAXWORD 100

struct nlist{
struct nlist *next;
char *name;
char *defn;
};
void error(int, char*);
int getch(void);
void getdef(void);
int getword(char *,int);
struct nlist *install(char *,char *);
struct nlist *lookup(char *);
void skipblanks(void);
void undef(char *);
void ungetch(int);
void ungets(char *);


//simple version of #define processor
main()
{
char w[MAXWORD];
struct nlist *p;
while(getword(w, MAXWORD) != EOF)
if(strcmp(w, "#") == 0)
getdef();
else if(!isalpha(w[0]))
printf("%s",w);
else if ((p == lookup(w)) == NULL)
printf("%s",w);
else
ungets(p->defn);
}

//getdef:get defination and install it
void getdef()
{
int c,i;
char def[MAXWORD], dir[MAXWORD], name[MAXWORD];
skipblanks();
if(!isalpha(getword(dir,MAXWORD)))
error(dir[0],"getdef:expecting a directve after #");
else if(strcmp(dir,"define") == 0) {
skipblanks();
if(!isalpha(getword(name, MAXWORD)))
error(name[0],"getdef:non alpha name expected"):
else{
skipblanks();
for(i = 0;i < MAXWORD-1; i++)
if((def[i] = getch()) == EOF || def[i] == 'n')
break;
def[i] = '';
if(i <= 0)
error('n',"getdef:non alpha in define");
else
install(name, def);
}
}else if(strcmp(dir,"undef") == 0) {
skipblanks();
if(!isalpha(getword(name, MAXWORD)))
error(name[0],"getdef:non alphain undef"):
else
undef(name);
}else
error(dir[0],"getdef:expecting a directive after #");
}

//undef:remove a name and defination from the table
int undef(char * name) {
struct nlist * np1, * np2;

if ((np1 = lookup(name)) == NULL) /* name not found */
return 1;

for ( np1 = np2 = hashtab[hash(name)]; np1 != NULL;
np2 = np1, np1 = np1->next ) {
if ( strcmp(name, np1->name) == 0 ) { /* name found */

/* Remove node from list */

if ( np1 == np2 )
hashtab[hash(name)] = np1->next;
else
np2->next = np1->next;

/* Free memory */

free(np1->name);
free(np1->defn);
free(np1);

return 0;
}
}

return 1; /* name not found */
}

//error:print error message and skip the rest of the line
void error(int c, char *s)
{
printf("error:%sn",s);
while(c != EOF && c != 'n')
c = getch();
}

//skipblanks:skip blan and tab characters
void skipblanks()
{
int c;
while((c = getch()) == ' ' ||c == 't')
;
ungetch(c);
}

/*ungets: push string back onto the input*/
void ungets(char s[])
{
int len=strlen(s);
void ungetch(int);
while (len >0)
ungetch(s[--len]);
}
/*note: modify the getword function to return
spaces so that the output resembles the input data.*/
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K & R C Programs Exercise 6-5.

K and R C, Solution to Exercise 6-5:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
Write a function undef that will remove a name and definition from the table maintained by lookup and install. Read more about C Programming Language .

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* for personal and learning purposes. For permissions to use the
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*
* Happy Coding
***********************************************************/
int undef(char * name) {
struct nlist * np1, * np2;

if ((np1 = lookup(name)) == NULL) /* name not found */
return 1;

for ( np1 = np2 = hashtab[hash(name)]; np1 != NULL;
np2 = np1, np1 = np1->next ) {
if ( strcmp(name, np1->name) == 0 ) { /* name found */

/* Remove node from list */

if ( np1 == np2 )
hashtab[hash(name)] = np1->next;
else
np2->next = np1->next;

/* Free memory */

free(np1->name);
free(np1->defn);
free(np1);

return 0;
}
}

return 1; /* name not found */
}


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K & R C Programs Exercise 6-4.

K and R C, Solution to Exercise 6-4:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
Write a C Program that prints the distinct words in its input sorted into decreasing order of frequency of occurrence. Precede each word by its count. Read more about C Programming Language .

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*
* Happy Coding
***********************************************************/


#include<stdio.h>
#include<ctype.h>

#define MAXWORD 100
#define NDISTINCT 1000

struct tnode(
char *word;
int count;
struct tnode *addtree(struct tnode *, char *);
int getword(char *, int);
void sortlist(void);
void treestore(struct tnode *);
struct tnode *list[DISTINCT];
int ntn = 0;

/* print distinct words sorted in decreasing order of freq.*/
main()
{
struct tnode *root;
char word[MAXWORD]
int i;

root = NULL;
while(getword(word, MAXWORD) != EOF)
if(isalpha(word[0]))
root = addtree(root, word);
treestore(root);
sortlist();
for(i = 0;i < ntn; i++)
printf("%2d:%20sn",list[i]->count,list[i]->word);
return 0;
}

//getword: get next word or character from input
int getword(char *word, int lim)
{
int c, d, comment(void), getch(void);
void ungetch(int);
char *w = word;
while(isspace(c = getch()))
;
if(c !=EOF)
*w++ = c;
if(isalpha(c) || c == '-' || c == '#'){
for(; --lim > 0; w++)
if(!isalnum(*w = getch()) && *w != '-') {
ungetch(*w);
break;
}
}
else if(c == ''' || c == '\'){
for( ; --lim > 0; w++)
if(((*w = getch()) == '\')
*++w = getch();
else if(*w == c) {
w++;
break;
}else if(*w == EOF)
break;
}else if(c == '/')
if((d = getch()) == '*')
c = comment();
else
ungetch(d);
*w = '';
return c;
}


//comment: skip over comment and return a character
int comment()
{
int c;
while((c = getch()) != EOF)
if(c == '*')
if((c = getch()) == '/')
break;
else
ungetch(c);
return c;
}

//TREESTORE:STORE IN LIST[] POINTERS TO TREE NODES

void treestore(struct tnode *p)
{
if(p != NULL) {
treestore(p->left);
if(ntn < NDISTINCT)
list[ntn++] = p;
treestore(p->right);
}
}

//sortlist: sort list of pointers to tree nodes
void sortlist()
{
int gap, i,j;
struct tnode *temp;

for(gap = ntn/2;gap > 0;gap /= 2)
for(i = gap; i < ntn;i++)
for(j = i - gap;j >= 0;j -= gap) {
if((list[j]->count) >= (list[j+gap]->count))
break;
temp = list[j];
list[j] = list[j+gap];
list[j+gap] = temp;
}
}
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K & R C Programs Exercise 6-3

K and R C, Solution to Exercise 6-3:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
C Program to Write a cross-referencer program that prints a list of all words in a document, and, for each word, a list of the line numbers on which it occurs. Remove noise words like “the”, “and,” and so on. Read more about C Programming Language .

/***********************************************************
* You can use all the programs on www.c-program-example.com
* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact [email protected]
* To find more C programs, do visit www.c-program-example.com
* and browse!
* Original URL: http://www.c-program-example.com/2012/02/k-r-c-programs-exercise-6-3.html
* GitHub URL: https://github.com/snadahalli/cprograms/blob/master/knrc/knrc6_3.c
***********************************************************/

/** Write a cross-referencer program that prints a list of all words in a
* document, and, for each word, a list of the line numbers on which it
* occurs. Remove noise words like "the", "and," and so on.
**/

#include
#include
#include
#include

char *dupstr(char *s) {
char *p = NULL;
if(s != NULL){
p = malloc(strlen(s) + 1);
if(p) {
strcpy(p, s);
}
}
return p;
}

int i_strcmp(const char *s, const char *t) {
int diff = 0;
char cs = 0;
char ct = 0;

while(diff == 0 && *s != '' && *t != '') {
cs = tolower((unsigned char)*s);
ct = tolower((unsigned char)*t);
if(cs < ct) {
diff = -1;
}
else if(cs > ct) {
diff = 1;
}
++s;
++t;
}

if(diff == 0 && *s != *t) {
if(*s == '') {
diff = -1;
}
else {
diff = 1;
}
}

return diff;
}

struct linelist {
struct linelist *next;
int line;
};

struct wordtree {
char *word;
struct linelist *firstline;
struct wordtree *left;
struct wordtree *right;
};

void printlist(struct linelist *list) {
if(list != NULL) {
printlist(list->next);
printf("%6d ", list->line);
}
}

void printtree(struct wordtree *node) {
if(node != NULL) {
printtree(node->left);
printf("%18s ", node->word);
printlist(node->firstline);
printf("n");
printtree(node->right);
}
}

struct linelist *addlink(int line) {
struct linelist *new = malloc(sizeof *new);
if(new != NULL) {
new->line = line;
new->next = NULL;
}
return new;
}

void deletelist(struct linelist *listnode) {
if(listnode != NULL) {
deletelist(listnode->next);
free(listnode);
}
}

void deleteword(struct wordtree **node) {
struct wordtree *temp = NULL;
if(node != NULL) {
if(*node != '') {
if((*node)->right != NULL) {
temp = *node;
deleteword(&temp->right);
}
if((*node)->left != NULL) {
temp = *node;
deleteword(&temp->left);
}
if((*node)->word != NULL) {
free((*node)->word);
}
if((*node)->firstline != NULL) {
deletelist((*node)->firstline);
}
free(*node);
*node = NULL;
}
}
}

struct wordtree *addword(struct wordtree **node, char *word, int line) {
struct wordtree *wordloc = NULL;
struct linelist *newline = NULL;
struct wordtree *temp = NULL;
int diff = 0;

if(node != NULL && word != NULL) {
if(NULL == *node) {
node = malloc(sizeof **node);
if(NULL != *node) {
(*node)->left = NULL;
(*node)->right = NULL;
(*node)->word = dupstr(word);
if((*node)->word != NULL) {
(*node)->firstline = addlink(line);
if((*node)->firstline != NULL) {
wordloc = *node;
}
}
}
}
else {
diff = i_strcmp((*node)->word, word);
if(0 == diff) {

newline = addlink(line);
if(newline != NULL) {
wordloc = *node;
newline->next = (*node)->firstline;
(*node)->firstline = newline;
}
}
else if(0 < diff) {
temp = *node;
wordloc = addword(&temp->left, word, line);
}
else {
temp = *node;
wordloc = addword(&temp->right, word, line);
}
}
}

if(wordloc == NULL) {
deleteword(node);
}

return wordloc;
}


char *char_in_string(char *s, int c) {
char *p = NULL;

/* if there's no data, we'll stop */
if(s != NULL) {
if(c != '') {
while(*s != '' && *s != c) {
++s;
}
if(*s == c) {
p = s;
}
}
}
return p;
}

char *tokenise(char **s, char *delims) {
char *p = NULL;
char *q = NULL;

if(s != NULL && *s != '' && delims != NULL) {
/* pass over leading delimiters */
while(NULL != char_in_string(delims, **s)) {
++*s;
}
if(**s != '') {
q = *s + 1;
p = *s;
while(*q != '' && NULL == char_in_string(delims, *q)) {
++q;
}

*s = q + (*q != '');
*q = '';
}
}

return p;
}

int NoiseWord(char *s)
{
int found = 0;
int giveup = 0;

char *list[] = {
"a",
"an",
"and",
"be",
"but",
"by",
"he",
"I",
"is",
"it",
"off",
"on",
"she",
"so",
"the",
"they",
"you"
};

int top = sizeof list / sizeof list[0] - 1;
int bottom = 0;
int guess = top / 2;

int diff = 0;

if(s != NULL) {
while(!found && !giveup) {
diff = i_strcmp(list[guess], s);
if(0 == diff) {
found = 1;
}
else if(0 < diff) {
top = guess - 1;
}
else {
bottom = guess + 1;
}
if(top < bottom) {
giveup = 1;
}
else {
guess = (top + bottom) / 2;
}
}
}

return found;
}

char *GetLine(char *s, int n, FILE *fp) {
int c = 0;
int done = 0;
char *p = s;

while(!done && --n > 0 && (c = getc(fp)) != EOF) {
if((*p++ = c) == 'n') {
done = 1;
}
}

*p = '';
if(EOF == c && p == s) {
p = NULL;
}
else {
p = s;
}
return p;
}

#define MAXLINE 8192

int main(void) {
static char buffer[MAXLINE] = {0};
char *s = NULL;
char *word = NULL;
int line = 0;
int giveup = 0;
struct wordtree *tree = NULL;

char *delims = " tnrafv!"%^&*()_=+{}[]\|/,.<>:;#~?";

while(!giveup && GetLine(buffer, sizeof buffer, stdin) != NULL) {
++line;
s = buffer;
while(!giveup && (word = tokenise(&s, delims)) != NULL) {
if(!NoiseWord(word)) {
if(NULL == addword(&tree, word, line)) {
printf("Error adding data into memory. Giving up.n");
giveup = 1;
}
}
}
}

if(!giveup) {
printf("%18s Line Numbersn", "Word");
printtree(tree);
}

deleteword(&tree);
return 0;
}
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K & R C Programs Exercise 6-2.

K and R C, Solution to Exercise 6-2:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
Write a C program that reads a C program and prints in alphabetical order each group of variable names that are identical in the first 6 characters, but different somewhere thereafter. Don’t count words within strings and comments. Make 6 a parameter that can be from the command line. Read more about C Programming Language .

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* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact [email protected]
* To find more C programs, do visit www.c-program-example.com
* and browse!
*
* Happy Coding
***********************************************************/

#include<stdio.h>
#include<ctype.h>
#include<string.h>
#include<stdlib.h>

struct tnode {
char *word;
int match;
struct tnode *left;
struct tnode *right;
};
#define MAXWORD
#define YES 0
#define NO 0

struct tnode *addtreex(struct tnode *, char *,int, int);
void treexprint(struct tnode *);
int getword(char *,int);


main(int argc, char argv[])
{
struct tnode *root;
char word[MAXWORD];
int found = NO;
int num;

num = (--argc && (*++argv)[0] == '-') ? atoi(argv[0] +1) : 6;
root = NULL;
while(getword(word, MAXWORD) != EOF) {
if(isalpha(word[0]) && strlen(word) >= num)
root = addtreex(root, word, num, &found);
found = NO;
}
treexprint(root);
return 0;
}
struct tnode *talloc(void);
int compare(char *,struct tnode *, int, int *);
//addtreex: add a node with w, at or below p
struct tnode *addtreex(struct tnode *p, char *w,int num, int *found)
{
int cond;
if(p == NULL) {
p = talloc();
p->word = strdup(w);
p->match = *found;
p->left = p->right = NULL;
}
else if((cond = compare(w,p,num,found)) < 0)
p->left = addtreex(p->left, w, num, found);
else if(cond > 0)
p->right = addtreex(p->right, w, num, found);
return p;
}

//compare:compare words and update p->match
int compare(char *s,struct tnode *p, int num, int *found)
{
int i;
char *t = p->word;
for(i = 0; *s == *t;i++,s++,t++)
if(*s == '')
return 0;
if(i >= num) {
*found = YES;
p->match = YES;
}
return *s - *t;
}

/*treexprint: in-order print of tree p if p->match == YES */
void treexprint(struct tnode *p)
{
if(p != NULL) {
treexprint(p->left);
if(p->match)
printf("%sn",p->word);
treexprint(p->right);
}
}


//getword: get next word or character from input
int getword(char *word, int lim)
{
int c, d, comment(void), getch(void);
void ungetch(int);
char *w = word;
while(isspace(c = getch()))
;
if(c !=EOF)
*w++ = c;
if(isalpha(c) || c == '-' || c == '#'){
for(; --lim > 0; w++)
if(!isalnum(*w = getch()) && *w != '-') {
ungetch(*w);
break;
}
}
else if(c == ''' || c == '\'){
for(; --lim > 0; w++)
if(((*w = getch()) == '\')
*++w = getch();
else if(*w == c) {
w++;
break;
}else if(*w == EOF)
break;
}else if(c == '/')
if((d = getch()) == '*')
c = comment();
else
ungetch(d);
*w = '';
return c;
}

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K & R C Programs Exercise 6-1.

K and R C, Solution to Exercise 6-1:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
C Program to write a routine that properly handles underscores, string constants, comments, or preprocessor control lines.Read more about C Programming Language .

/***********************************************************
* You can use all the programs on www.c-program-example.com
* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact [email protected]
* To find more C programs, do visit www.c-program-example.com
* and browse!
*
* Happy Coding
***********************************************************/

#include<stdio.h>
#include<ctype.h>
//getword: get next word or character from input
int getword(char *word, int lim)
{
int c, d, comment(void), getch(void);
void ungetch(int);
char *w = word;
while(isspace(c = getch()))
;
if(c !=EOF)
*w++ = c;
if(isalpha(c) || c == '-' || c == '#'){
for(; --lim > 0; w++)
if(!isalnum(*w = getch()) && *w != '-') {
ungetch(*w);
break;
}
}
else if(c == ''' || c == '\'){
for( ; --lim > 0; w++)
if(((*w = getch()) == '\')
*++w = getch();
else if(*w == c) {
w++;
break;
}else if(*w == EOF)
break;
}else if(c == '/')
if((d = getch()) == '*')
c = comment();
else
ungetch(d);
*w = '';
return c;
}

//comment: skip over comment and return a character
int comment()
{
int c;
while((c = getch()) != EOF)
if(c == '*')
if((c = getch()) == '/')
break;
else
ungetch(c);
return c;
}

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C Program to find the even numbers square and sum from 1 to 10.

C Program to find the even numbers square and sum from 1 to 10.
Even number is an integer, which is the multiple of two. In this program we use the for loop to produce the even numbers. Try to change the for loop limits you can get the various range results. Read more about C Programming Language .

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* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact [email protected]
* To find more C programs, do visit www.c-program-example.com
* and browse!
*
* Happy Coding
***********************************************************/

#include<stdio.h>
#include<conio.h>
int main()
{
int i,j,sum = 0;
clrscr();
printf("nEven numbers and their squares from 1 to 10:n");
for(i =1; i <=10; i++)
{
if(i % 2 == 0)
{
j = i * i;
printf("%dtt%d",i,j);
printf("n");
sum = sum + j;
}
}
printf("nnSum of even numbers square from 1 to 10 is: %d",sum);
return 0;

}
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K & R C Programs Exercise 5-20.

K and R C, Solution to Exercise 5-20:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
C Program to expand dcl to handle declarations with function argument types, qualifiers like const, and so on. Read more about C Programming Language .

/***********************************************************
* You can use all the programs on www.c-program-example.com
* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact [email protected]
* To find more C programs, do visit www.c-program-example.com
* and browse!
*
* Happy Coding
***********************************************************/


#include<stdio.h>
#include<string.h>
#include<ctype.h>
enum { NAME, PARENS, BRACKETS};
enum { NO, YES};
void dcl(void);
void dirdcl(void);
void errmsg(char *);
void dclspec(void);
int typespec(void);
int typeequal(void);
int compare(char **, char**);
void parmdcl(void);

int gettoken(void);
extern int tokentype;
extern char token[];
extern char name[];
extern char datatype[];
extern char out[];
extern int prevtoken;


//dcl:parse a declarator
void dcl(void)
{
int ns;
for(ns = 0; gettoken() == '*';)
ns++;
dirdcl();
while(ns --> 0)
strcat(out, "pointer to");
}


//dirdcl: parse a direct declaration
void dirdcl(void)
{
int type;
void parmdcl(void);
if(tokentype == '('){
dcl();
if(tokentype != ')')
errmsg("error:missimg)n");
}
else if(tokentype == NAME){
if(name[0] == '')
strcpy(name,token);
}else
prevtoken = YES;
while((type = gettoken()) == PARENS || type == BRACKETS || type == '(')
if(type == PARENS)
strcat(out, "function returning");
else if(type == '('){
strcat(out, "function expecting");
parmdcl();
strcat(out, "and returning");
} else{


strcat(out, "array");
strcat(out, token);
strcat(out, "of");
}
}

//errmsg: prints the error message
void errmsg(char *msg)
{
printf("%sn",msg);
prevtoken = YES;
}


//get token:return next token
int gettoken(void)
{
int c, getch(void);
void ungetch(int);
char *p = token;
if(prevtoken == YES) {
prevtoken = NO;
return tokentype;
while((c = getch()) == ' ' || c == 't')
;
if(c == '('){
if ((c = getch()) == ')'){
strcpy(token,"()");
return tokentype = PARENS;
}
else{
ungetch(c);
return tokentype = '(';
}
}
else if(c == '['){
for(*p++ = c; (*p++ = getch()) != ']';)
;
*p = '';
return tokentype = BRACKETS;
}
else if (isalpha(c)) {
for(*p++ = c; isalnum(c = getch());)
*p++ = c;
*p = '';
ungetch(c);
return tokentype = NAME;
} else
return tokentype = c;
}



//parmdcl: parse a parameter declarator
void parmdcl(void)
{
do{
dclspec();
}while (tokentype == ',');
if(tokentype != ')')
errmsg("missing ) in parameter declarationn");
}

//dclspec: declaration specification
void dclspec(void)
{
char temp[MAXTOKEN];
temp[0] = '';
gettoken();
do{
if(tokentype != NAME){
prevtoken = YES;
dcl();
}else if(typedesc() == YES){
strcat(temp," ");
strcat(temp, token);
gettoken();
}else if(typeequal() == YES){
strcat(temp," ");
strcat(temp, token);
gettoken();
}else
errmsg("unknown type parameter listn");
}while(tokentype != ',' && tokentype != ')');
strcat(out,temp);
if(tokentype == ',');
strcat(out,",");
}

//typedesc: return yes if token is type-specifier
int typespec(void)
{
static char *types[] = {
"char",
"int",
"void"
};
char *pt = token;
if(bsearch(&pt, types,sizeof(types)/sizeof(char *),
sizeof(char *),compare) == NULL)
return NO;
else
return YES;
}

//typeequal:return YES if token is a type qualifier
int typeequal(void)
{
static char *typeq[] = {
"const",
"volatite"
};
char *pt = token;
if(bsearch(&pt, typeq,sizeof(typeq)/sizeof(char *),
sizeof(char *),compare) == NULL)
return NO;
else
return YES;

}

//compare: compare two strings for bsearch
int compare(char **s, char **s)
{
return strcmp(*s, *t);
}
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K & R C Programs Exercise 5-19.

K and R C, Solution to Exercise 5-19:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
C Program to modify(K & R C Programs Exercise 5-18.) undcl so that it does not add redundant parentheses to declarations. Read more about C Programming Language .

/***********************************************************
* You can use all the programs on www.c-program-example.com
* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact [email protected]
* To find more C programs, do visit www.c-program-example.com
* and browse!
*
* Happy Coding
***********************************************************/

#include<stdio.h>
#include<string.h>
#include<ctype.h>

#define MAXTOKEN 100

enum { NAME, PARENS, BRACKETS};
enum { YES, NO};



int gettoken(void);
int nexttoken(void);
extern int tokentype;
extern char token[MAXTOKEN];
char out[1000];
extern int prevtoken = NO;
//UNDCL:convert word description to declaration
main()
{
int type;
char temp[MAXTOKEN];
while (gettoken() !=EOF) {
strcy(out, token);
while ((type = gettoken()) != 'n')
if(type == PARENS || type == BRACKETS)
strcat(out, token);
else if(type == '*') {
if((type = nexttoken()) == PARENS || type == BRACKETS)
sprintf(temp, "(*%s)", out);
else
sprintf(temp, "*%s", out);
strcpy(out, temp);

}else if(type == NAME){
sprintf(temp, "%s%s",token, out);
strcpy(out, temp);
}else
printf("Invalid input at %sn",token);
printf("%sn",out);
}
return 0;
}


//nexttoken: get the next token and push it back
int nexttoken(void)
{
int type;
extern int prevtoken;
type = gettoken();
prevtoken = YES;
return type;
}


//get token:return next token
int gettoken(void)
{
int c, getch(void);
void ungetch(int);
char *p = token;
if(prevtoken == YES) {
prevtoken = NO;
return tokentype;
}
while((c = getch()) == ' ' || c == 't')
;
if(c == '('){
if ((c = getch()) == ')'){
strcpy(token,"()");
return tokentype = PARENS;
}
else{
ungetch(c);
return tokentype = '(';
}
}
else if(c == '['){
for(*p++ = c; (*p++ = getch()) != ']';)
;
*p = '';
return tokentype = BRACKETS;
}
else if (isalpha(c)) {
for(*p++ = c; isalnum(c = getch());)
*p++ = c;
*p = '';
ungetch(c);
return tokentype = NAME;
} else
return tokentype = c;
}


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C program To show examples of the strtol function.

C program To show examples of the strtol function.
strtol() function converts the string to the long integer, and strtol() can accept the number in various bases, and converts it into the decimal number or base. Read more about C Programming Language .

/***********************************************************
* You can use all the programs on www.c-program-example.com
* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact [email protected]
* To find more C programs, do visit www.c-program-example.com
* and browse!
*
* Happy Coding
***********************************************************/

#include <stdlib.h>

main()
{
char num[10];

/* Test a valid number */
strcpy(num,"13");

printf("%s(Oct) is %i(Dec)n", num, strtol(num, NULL, 8));
printf("%s(Dec) is %i(Dec)n", num, strtol(num, NULL, 10));
printf("%s(hex) is %i(Dec)n", num, strtol(num, NULL, 16));

puts("----------------------------------");

/* Test a slightly valid number
* Returns the same results as
* above. */
strcpy(num, "13hzcd");

printf("%s(Oct) is %i(Dec)n", num, strtol(num, NULL, 8));
printf("%s(Dec) is %i(Dec)n", num, strtol(num, NULL, 10));
printf("%s(hex) is %i(Dec)n", num, strtol(num, NULL, 16));

puts("----------------------------------");

/* Test an invalid number
* Returns ZERO */
strcpy(num, "hzcd");

printf("%s(Oct) is %i(Dec)n", num, strtol(num, NULL, 8));
printf("%s(Dec) is %i(Dec)n", num, strtol(num, NULL, 10));
printf("%s(hex) is %i(Dec)n", num, strtol(num, NULL, 16));


puts("----------------------------------");

/* Test 0 base.
* This will look at the number
* and decide the base for its self!
*/
strcpy(num, "13");
printf("%s is %i(Dec)n", num, strtol(num, NULL, 0));

strcpy(num, "013");
printf("%s is %i(Dec)n", num, strtol(num, NULL, 0));

strcpy(num, "0x13");
printf("%s is %i(Dec)n", num, strtol(num, NULL, 0));

}
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C Strings

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