Free C Program

C Program to solve the producer consumer problem

Posted on by Sandeepa Nadahalli
Write a C Program to solve the producer consumer problem with two processes using semaphores.
Producer-consumer problem is the standard example of multiple process synchronization problem. The problem occurs when concurrently producer and consumer tries to fill the data and pick the data when it is full or empty. producer consumer problem is also known as bounded-buffer problem. In this program We use the semaphores, to solve the problem.Read more about C Programming Language . and read the C Programming Language (2nd Edition) by K and R. 
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#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <time.h>
#include <sys/types.h>
#include <sys/ipc.h>
#include <sys/sem.h>


#define NUM_LOOPS 20
int main(int argc, char* argv[])
{
    int sem_set_id;
    union semun sem_val;
    int child_pid;
    int i;
    struct sembuf sem_op;
    int rc;
    struct timespec delay;


    sem_set_id = semget(IPC_PRIVATE, 1, 0600);
    if (sem_set_id == -1) {
        perror("main: semget");
        exit(1);
    }
    printf("Semaphore set created,
    semaphore set id '%d'.n", sem_set_id);


    sem_val.val = 0;
    rc = semctl(sem_set_id, 0, SETVAL, sem_val);
    child_pid = fork();
    switch (child_pid) {
        case -1:
        perror("fork");
        exit(1);
        case 0:
        for (i=0; i<NUM_LOOPS; i++) {
            sem_op.sem_num = 0;
            sem_op.sem_op = -1;
            sem_op.sem_flg = 0;
            semop(sem_set_id, &sem_op, 1);
            printf("consumer: '%d'n", i);
            fflush(stdout);
            sleep(3);
        }
        break;
        default:
        for (i=0; i<NUM_LOOPS; i++)
        {
            printf("producer: '%d'n", i);
            fflush(stdout);
            sem_op.sem_num = 0;
            sem_op.sem_op = 1;
            sem_op.sem_flg = 0;
            semop(sem_set_id, &sem_op, 1);
            sleep(2);
            if (rand() > 3*(RAND_MAX/4))
            {
                delay.tv_sec = 0;
                delay.tv_nsec = 10;
                nanosleep(&delay, NULL);
            }
        }
        break;
    }


    return 0;
}
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C Program to check whether two strings are anagrams of each other.

Posted on by Sandeepa Nadahalli
C Strings:
Write a c program to check whether two strings are anagrams of each other.
Two strings are said to be anagrams, if the characters in the strings are same in terms of numbers and value ,only arrangement or order of characters are may be different.
Example: “dfghjkl” and “lkjghdf” are anagrams of each other.
Read more about C Programming Language . and read the C Programming Language (2nd Edition). by K and R.
/***********************************************************
* You can use all the programs on  www.c-program-example.com
* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact info@c-program-example.com
* To find more C programs, do visit www.c-program-example.com
* and browse!
* 
*                      Happy Coding
***********************************************************/

#include<stdio.h>
#include<string.h>
# define NO_OF_CHARS 256
int Anagram(char *str1, char *str2)
{
    // Create two count arrays and initialize all values as 0
    int count1[NO_OF_CHARS] = {0};
    int count2[NO_OF_CHARS] = {0};
    int i;
    
    // For each character in input strings, increment count in
    // the corresponding count array
    for (i = 0; str1[i] && str2[i];  i++)
    {
        count1[str1[i]]++;
        count2[str2[i]]++;
    }
    
    // If both strings are of different length. Removing this condition
    // will make the program fail for strings like "aaca" and "aca"
    if (str1[i] || str2[i])
    return 0;
    
    // Compare count arrays
    for (i = 0; i < NO_OF_CHARS; i++)
    if (count1[i] != count2[i])
    return 0;

    return 1;
}
main()
{
    char str[100], str1[100];
    int flag = 0;
    
    printf("Enter first stringn");
    gets(str);
    
    printf("Enter second stringn");
    gets(str1);
    
    flag=Anagram(str, str1);
    if (flag==1)
    printf(""%s" and "%s" are anagrams.n", str, str1);
    else
    printf(""%s" and "%s" are not anagrams.n", str, str1);
    
    return 0;
}

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C Program to check matrix is magic square or not

Posted on by Sandeepa Nadahalli

Write a c program to check whether the given matrix is a magic square matrix or not.

A matrix is magic square matrix, if all rows sum, columns sum and diagonals sum are equal.

Example:
8   1   6
3   5   7
4   9   2

is the magic square matrix. As you can see numbers in first row add up to 15 (8 + 1 + 6), so do the numbers of 2nd row 3 + 5 + 7. Also the number in the last row 4 + 9 + 2. Similarly, the columns all add up to the same number 15. Hence, this matrix is a magic square matrix.

The Program

#include <stdio.h>
void main() {
int A[50][50];
int i, j, M, N;
int size;
int rowsum, columnsum, diagonalsum;
int magic = 0;
printf("Enter the order of the matrix:\n");
scanf("%d %d", &M, &N);
if(M==N) {
printf("Enter the elements of matrix \n");
for(i=0; i<M; i++) {
for(j=0; j<N; j++) {
scanf("%d", &A[i][j]);
}
}
printf("\n\nMATRIX is\n");
for(i=0; i<M; i++) {
for(j=0; j<N; j++) {
printf("%3d\t", A[i][j]);
}
printf("\n");
}
// calculate diagonal sum
diagonalsum = 0;
for(i=0; i<M; i++) {
for(j=0; j<N; j++) {
if(i==j) {
diagonalsum = diagonalsum + A[i][j];
}
}
}
// calculate row sum
for(i=0; i<M; i++) {
rowsum = 0;
for(j=0; j<N; j++) {
rowsum = rowsum + A[i][j];
}
if(rowsum != diagonalsum) {
printf("\nGiven matrix is not a magic square");
return;
}
}
// calculate column sum
for(i=0; i<M; i++) {
columnsum = 0;
for(j=0; j<N; j++) {
columnsum = columnsum + A[j][i];
}
if(columnsum != diagonalsum) {
printf("\nGiven matrix is not a magic square");
return;
}
}
printf("\nGiven matrix is a magic square matrix");
} else {
printf("\n\nPlease enter the square matrix order(m=n) \n\n");
}
}
view raw magic_square.c hosted with ❤ by GitHub

Sample Output

Read more about C Programming Language and read the C Programming Language (2nd Edition). by K and R.

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C Program to delete vowels in a string.

Posted on by Sandeepa Nadahalli
C Strings:
Write a C Program to delete a vowel in a given string.
In this program, We use the pointers to position the characters.check_vowel() function checks the character is vowel or not, if the character is vowel it returns true else false.
Example output:Given string: Check vowel
Output is: Chck vwl
Read more about C Programming Language . and read the C Programming Language (2nd Edition). by K and R. 

/***********************************************************
* You can use all the programs on  www.c-program-example.com
* for personal and learning purposes. For permissions to use the
* programs for commercial purposes,
* contact info@c-program-example.com
* To find more C programs, do visit www.c-program-example.com
* and browse!
* 
*                      Happy Coding
***********************************************************/

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<conio.h>
#define TRUE 1
#define FALSE 0

int check_vowel(char);

main()
{
    char string[100], *temp, *pointer, ch, *start;
    csrcscr();
    printf("nnEnter a stringn");
    scanf("%s",string);
    temp = string;
    pointer = (char*)malloc(100);

    if( pointer == NULL )
    {
        printf("Unable to allocate memory.n");
        exit(EXIT_FAILURE);
    }

    start = pointer;

    while(*temp)
    {
        ch = *temp;

        if ( !check_vowel(ch) )
        {
            *pointer = ch;
            pointer++;
        }
        temp++;
    }
    *pointer = '