K and R C, Solution to Exercise 3-3:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition)
. You can learn and solve K&R C Programs Exercise.
C Program to expand short hand notations like a-z in the string s1 into the equivalent complete list abc—xyz in s2. Allowed for letters of either case and digits, and be prepared to handle cases like a-b-c and a-z0-9 and -a-z. Arranged that a leading or trailing – is taken literally. Read more about C Programming Language .
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition)
. You can learn and solve K&R C Programs Exercise.C Program to expand short hand notations like a-z in the string s1 into the equivalent complete list abc—xyz in s2. Allowed for letters of either case and digits, and be prepared to handle cases like a-b-c and a-z0-9 and -a-z. Arranged that a leading or trailing – is taken literally. Read more about C Programming Language .
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#include
#include
void expand(char * s1, char * s2);
int main(void) {
char *s[] = { "a-z-", "z-a-", "-1-6-",
"a-ee-a", "a-R-L", "1-9-1",
"5-5", NULL };
char result[100];
int i = 0;
while ( s[i] ) {
expand(result, s[i]);
printf("Unexpanded: %sn", s[i]);
printf("Expanded : %sn", result);
++i;
}
return 0;
}
//expand: expand short hand notations in s1 into string s2
void expand(char * s1, char * s2) {
static char upper_alph[27] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
static char lower_alph[27] = "abcdefghijklmnopqrstuvwxyz";
static char digits[11] = "0123456789";
char * start, * end, * p;
int i = 0;
int j = 0;
/* Loop through characters in s2 */
while ( s2[i] ) {
switch( s2[i] ) {
case '-':
if ( i == 0 || s2[i+1] == ' ' ) {
s1[j++] = '-';
++i;
break;
}
else {
if ( (start = strchr(upper_alph, s2[i-1])) &&
(end = strchr(upper_alph, s2[i+1])) )
;
else if ( (start = strchr(lower_alph, s2[i-1])) &&
(end = strchr(lower_alph, s2[i+1])) )
;
else if ( (start = strchr(digits, s2[i-1])) &&
(end = strchr(digits, s2[i+1])) )
;
else {
fprintf(stderr, "EX3_3: Mismatched operands '%c-%c'n",
s2[i-1], s2[i+1]);
s1[j++] = s2[i-1];
s1[j++] = s2[i++];
break;
}
p = start;
while ( p != end ) {
s1[j++] = *p;
if ( end > start )
++p;
else
--p;
}
s1[j++] = *p;
i += 2;
}
break;
default:
if ( s2[i+1] == '-' && s2[i+2] != ' ' ) {
++i;
}
else {
s1[j++] = s2[i++];
}
break;
}
}
s1[j] = s2[i];
}
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