C program to simulate a simple calculator using switch statement. The calculator should be able to perform basic arithmetic operations like addition, subtraction, multiplication, and division only on integers. Error message should be reported, if any attempt is made to divide by zero. (Using switch statement) . Read more about C Programming Language .
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#include<stdio.h> | |
int main() { | |
int num1,num2,opt; | |
printf("Enter the first Integer:\n"); | |
scanf("%d",&num1); | |
printf("Enter the second Integer:\n"); | |
scanf("%d",&num2); | |
for(;;) { | |
printf("\n\n\n\nEnter the your option:\n"); | |
printf("1-Addition.\n2-Substraction.\n3-Multiplication.\n4-Division.\n5-Exit.\n"); | |
scanf("%d",&opt); | |
switch(opt) { | |
case 1: | |
printf("\nAddition of %d and %d is: %d",num1,num2,num1+num2); | |
break; | |
case 2: | |
printf("\nSubstraction of %d and %d is: %d",num1,num2,num1-num2); | |
break; | |
case 3: | |
printf("\nMultiplication of %d and %d is: %d",num1,num2,num1*num2); | |
break; | |
case 4: | |
if(num2==0) { | |
printf("OOps Devide by zero\n"); | |
} else { | |
printf("\n Division of %d and %d is: %d",num1,num2,num1/num2); | |
} | |
break; | |
case 5: | |
return 0; | |
break; | |
default: | |
printf("\n Enter correct option\n"); | |
break; | |
} | |
} | |
return 0; | |
} |
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