# K & R C Programs Exercise 4-3.

K and R C, Solution to Exercise 4-3:
K and R C Programs Exercises provides the solution to all the exercises in the C Programming Language (2nd Edition). You can learn and solve K&R C Programs Exercise.
Write a c program to implement Basic framework, it’s straight forward to extend the calculate. Add the modulus(%) operator and provisions for negative numbers. Read more about C Programming Language .

`/************************************************************ You can use all the programs on  www.c-program-example.com* for personal and learning purposes. For permissions to use the* programs for commercial purposes,* contact [email protected]* To find more C programs, do visit www.c-program-example.com* and browse!* *                      Happy Coding***********************************************************/#include<stdio.h>#include<math.h>       /*for atof()*/#define MAXTOP 100     /* max size of operand or operator  */#define NUMBER  '0'    /* SIGNAL THAT A NUMBER WAS FOUND   */int gettop(char []);void push(double);double pop(void);//reverse Polish calulatorint main(void){ int type; double op2; char s[MAXOP]; while((type = getop(s)) != EOF) {  switch(type)  {  case NUMBER:   push(atof(s));   break;  case '+':  push(pop() + pop());  break;  case '*':   push(pop() * pop());   break;  case '-':   op2=pop();   push(pop() - op2);   break;  case '-':   op2=pop();   if(op2 != 0.0)    push(pop() / op2);   else printf("nError: Zero divissorn")       break;  case '%':   op2 = pop();   if(op2)    push(fmod(pop(), op2));   else    printf("nError: Division by zero!");   break;  case 'n':   printf("t%.8gn",pop());   break;   default:   printf("error: unknown command %sn", s);   brak;  } } return 0;}/* Getop: get next operator or numeric operand. */int getop(char s[]){#define PERIOD  '.' int i = 0; int c; int next; /* Skip whitespace */ while((s[0] = c = getch()) == ' ' || c == 't')  ; s[1] = ''; /* Not a number but may contain a unary minus. */ if(!isdigit(c) && c != PERIOD && c != '-')  return c;                if(c == '-') {  next = getch();  if(!isdigit(next) && next != PERIOD)  {   return c;  }  c = next; } else {  c = getch(); } while(isdigit(s[++i] = c))  c = getch(); if(c == PERIOD)                     /* Collect fraction part. */  while(isdigit(s[++i] = c = getch()))   ; s[i] = ''; if(c != EOF)  unGetch(c); return NUMBER;#define MAXVAL 100int sp = 0;          /* Next free stack position. */double val[MAXVAL];  /* value stack. *//* push: push f onto stack. */void push(double f){    if(sp < MAXVAL)        val[sp++] = f;    else         printf("nError: stack full can't push %gn", f);}/*pop: pop and return top value from stack.*/double pop(void){    if(sp > 0)        return val[--sp];    else    {        printf("nError: stack emptyn");        return 0.0;    }}}`
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# C Program for simple calculator, using switch statement

C program to simulate a simple calculator using switch statement.  The calculator should be able to perform basic arithmetic operations like addition, subtraction, multiplication, and division only on integers. Error message should be reported, if any attempt is made to divide by zero. (Using switch statement) . Read more about C Programming Language .

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 /*********************************************************** * You can use all the programs on www.c-program-example.com * for personal and learning purposes. For permissions to use * the programs for commercial purposes, * contact [email protected] * To find more C programs, do visit www.c-program-example.com * and browse! * * Happy Coding ***********************************************************/ #include int main() { int num1,num2,opt; printf("Enter the first Integer:\n"); scanf("%d",&num1); printf("Enter the second Integer:\n"); scanf("%d",&num2); for(;;) { printf("\n\n\n\nEnter the your option:\n"); printf("1-Addition.\n2-Substraction.\n3-Multiplication.\n4-Division.\n5-Exit.\n"); scanf("%d",&opt); switch(opt) { case 1: printf("\nAddition of %d and %d is: %d",num1,num2,num1+num2); break; case 2: printf("\nSubstraction of %d and %d is: %d",num1,num2,num1-num2); break; case 3: printf("\nMultiplication of %d and %d is: %d",num1,num2,num1*num2); break; case 4: if(num2==0) { printf("OOps Devide by zero\n"); } else { printf("\n Division of %d and %d is: %d",num1,num2,num1/num2); } break; case 5: return 0; break; default: printf("\n Enter correct option\n"); break; } } return 0; }
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